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ARCHIVED REPORTS_XR0003765
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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HAZELTON
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375
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2900 - Site Mitigation Program
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PR0540905
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ARCHIVED REPORTS_XR0003765
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Last modified
2/3/2020 10:15:41 AM
Creation date
2/3/2020 9:07:46 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0003765
RECORD_ID
PR0540905
PE
2960
FACILITY_ID
FA0023406
FACILITY_NAME
SIERRA LUMBER MANUFACTURERS
STREET_NUMBER
375
Direction
W
STREET_NAME
HAZELTON
STREET_TYPE
AVE
City
STOCKTON
Zip
95205
APN
147120808
CURRENT_STATUS
01
SITE_LOCATION
375 W HAZELTON AVE
P_LOCATION
01
QC Status
Approved
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SJGOV\sballwahn
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EHD - Public
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' Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> • SIERRA LUMBER-375 West Hazelton Avenue, Stockton, CA <br />' Assumptions <br />' • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approxinniated <br />' The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' — M=C • Q • t <br /> where M—cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br />' Q—extraction flow rate (m`/hr) <br /> t=operational period(hrs) <br /> tThe average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> 1. 25 JUNE to 11 JULY 2001 <br />' The average analytical TPH-g concentration for this time interval was determined to be 1,250,ug/l(06-25-01=1,200,ug/L <br /> and 07-11-01 = 1,300 pg/L, avg = 1,250,ug/L) The average flow rates during this tune was calculated at 0 27 inches <br /> of water or approxmnately 29 cubic feet per minute(table 5),the operational penod was equal to 384 hours of panning <br /> time <br /> C = 1,250,ug/1=0 001250 kg/m` <br /> Q = 0 27 inches water = 29 fl-' <br /> /min <br /> t=384 hours <br /> Converting Q to m3/hour yields <br />' Q=(29 ft3/min) 0(60 rrun/hour) -(0 0283168m3/fl3)=49 27 m3/hour <br /> M=C - Q• t=(0 001250 kg/m`) -(49 27 m'/hour) • (3 84 hours)=23 65 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br />' 23 65 kg of gas• 2 2046 lbs of gas/kg of gas=52 14 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 52 14 lbs of gas • 0 16 gal of gas/lbs of gas = 8 34 gallons of gasoline <br /> I <br /> I <br />
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