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ARCHIVED REPORTS_XR0003766
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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HAZELTON
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2900 - Site Mitigation Program
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PR0540905
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ARCHIVED REPORTS_XR0003766
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Last modified
2/3/2020 10:15:39 AM
Creation date
2/3/2020 9:08:17 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0003766
RECORD_ID
PR0540905
PE
2960
FACILITY_ID
FA0023406
FACILITY_NAME
SIERRA LUMBER MANUFACTURERS
STREET_NUMBER
375
Direction
W
STREET_NAME
HAZELTON
STREET_TYPE
AVE
City
STOCKTON
Zip
95205
APN
147120808
CURRENT_STATUS
01
SITE_LOCATION
375 W HAZELTON AVE
P_LOCATION
01
QC Status
Approved
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SJGOV\sballwahn
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EHD - Public
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Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> SIERRA LUMBER- 375 West Hazelton Avenue, Stockton, CA <br /> IAssumptions <br /> I Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during <br /> the SVE pilot test(Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> IM=C• Q • t <br /> where M=cumulative mass recovered(kg) <br /> I C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br /> IThe average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 1. 16 APRIL to 27 APRIL 2001 <br /> • The average analytical TPH-g concentration for this time uaterval was determined to be 7,985 ug/1 (04-16-01= <br /> 14,000µg/L and 04-27-01 = 1,970,u.g/L, avg = 7,985 µg/L) The average flow rates during this time was <br /> calculated at 0 6 inches of water or approximately 42 cubic feet per minute(table 5), the operational period was equal <br /> to 288 hours of running time <br /> C = 7,985 ,ug/l=0 007985 kg/m' <br /> Q = 2 6 inches water = 84 ft'/min <br /> t=288 hours <br /> Converting Q to m'/hour yields <br /> Q=(42 ft'/min) •(60 rrun/hour)•(0 0283168m'Ift')=7136 m'/hour <br /> IM=C • Q • t=(0 007985 kg/m') -(7136 rri'Ihour) • (288 hours) = 164 1 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> I164 1 kg of gas • 2 2046 lbs of gas/kg of gas=361 78 lbs of gasoline <br /> IConverting pounds of gasoline to gallons of gasoline yields <br /> 36178 lbs of gas • 0 16 gal of gas/lbs of gas � 58 gallons of gasoline <br /> I <br />
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