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L Using 385 parts per million as the average concentration of gasoline from i l feet bsg to 15 feet bag, <br /> the volume of gasoline is: <br /> Lweight of soil • average concentration 4-29,984,615 g • 0.000385 0 11,544 g of gasoline <br /> LConverting grams of gasoline to volume of gasoline(gallons)using density of gasoline to equal 0.8: <br /> 11,544 g+0.8cm3/g a 14,430 cm3 <br /> i 14,430 cm3 • (1 gallon+3,785 cm3) - 3.81 gallons of gasoline <br /> L 3) Volume of contaminated soil at 15 feet bsg to 40 feet bsg: <br /> LV3==2•h —1 7r(7.5 ft ) • 25 ft s 4,418 ft a 164 yd' <br /> LConverting 164 yd3 to cm3yields approximately 124,935,895 cm3. Using 1.5 g/cm3 as the weight of <br /> soil, the total weight of contaminated soil is approximately 187,403,842 g. <br /> LBetween 15 feet bsg and 40 feet bsg, soil samples collected from soil probing P 1 had concentrations <br /> of 0.013, 0.0055, 0.039, and 0.0072 ppm, or an average concentration of 0.016 ppm. <br /> LUsing 0.016 parts per million as the average concentration of gasoline from 15 feet bsg to 40 feet bsg, <br /> the volume of gasoline is: <br /> Lweight of soil • average concentration 187,403,842 g • 0.000000016 a 2.9985 g of <br /> gasoline <br /> LConverting grams of gasoline to volume of gasoline(gallons)using density of gasoline to equal 0.8: <br /> L2.9985 g_0.8cm3/g a 3.7481 cm3 <br /> 3.7481 cm3 • (1 gallon-3,785 cm3) R 0.001 gallons of gasoline <br /> L <br /> 4) Volume of gasoline at 5 feet to 11 feet bsg(V), added to volume of gasoline at 11 feet to 15 <br /> L feet bsg (V2), added to volume of gasoline at 15 feet to 40 feet bsg (Vi ),yields the total <br /> volume of gasoline(V4). <br /> LV4= + V2+V3 = 13.15+3.81 +0.001 = 16.96 total gallons of gasoline <br /> L <br /> L <br /> L <br /> L <br />