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Nitrate Mass Balance Calculation <br /> 21300 Mann Road, Acampo <br /> Data Input: <br /> Effluent Quantity(Q): 420 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(NH,): 35.00 mg/L-N Denitrification(d): 25.0% <br /> Site Area(A): 1.66 Acres Deep Perc.of Rain(R): 5.29 in/yr <br /> Waste Loading (W): 3.40 in/yr <br /> Result: <br /> Mass Balance(N j: 10.9 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 109% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find CW <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A) acre <br /> 3.4 in/yr(site)=420 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/1.66 acres) <br /> N — WN 1( d1+RNb Hantzsche-Fennemore Equation(Nc1 <br /> --W _ <br /> W+R <br /> 10.88 mg/L-N=((3.4 in/yr x 35 mg/L-N x(1-0.25))+(5.29 in/yr x 1 mg/L-N))/(3.4 in/yr+5.29 in/yr) <br /> Variables: <br /> Nc =Average nitrate-N concentration(mg/I)of combined effluent and rainfall percolate(10.88 mg/L-N). <br /> W = Uniform waste water loading for study area(in/yr)(3.4 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R= Uniform deep percolation of rainfall (5.29 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 5.29 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> iftnetralogix <br /> Plate 9 <br />