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Volume and Mass Calculation of Dissolved MTBE VAN BUSKIRK GOLF COURSE FACILITY f� 1740 Houston Avenue, Stockton, California ' Assumptions: ' • The distribution of dissolved MTBE concentrations on the site can be approximated by an elliptical column, with an average concentration of MTBE (See Figure 4); ' • The effective porosity of soil at the site is 35% (probably overestimated); and • Data collected from the March 2001 ground water sampling event are representative of existing site conditions_ tThe area of an ellipsoid can be calculated by the formula: ' Ae = 7cab, where a is the long radius of the ellipsoid and b is the short radius. ' For the estimated ellipsoid, a=45 ft, b =20 ft, and thickness c �= 30 ft - The average MTBE concentration for the ellipsoid is estimated to be 100 micrograms per liter(ppb) ' These concentrations are equivalent to 0.000001 glml. As a ml is very nearly equivalent to a cubic centimeter of water, which by definition equals one gram, these concentrations are nearly unitless numbers relative to mass calculations. The area of the elliptical column is given by: ' A,,,=Tcab = Tc(45 ft)(20 ft) = 2827 ftz The volume of the inner elliptical column is given by: VC1 = Ae1 x c =2827 f12 x 30 ft = 84,823 fl ' Water occupies the porosity in the soil,which is estimated to be 35% of the soil volume, so the total volume of water in the saturated portion of the inner ellipsoid is approximated by: ' Vel = (.35)(84,823 ft) =27,143 ft' One cubic foot of water contains 7.48 gallons, so the volume of the water in the inner ellipsoid is ' given by: Vei = (27,143 ft3)(7.48 gal/ft)=203,032 gallons 1 One gallon of water equals 3.785 liter of water, so the volume of the water expressed as liters in the ' ellipsoid is given by: V=(203,032 gallons) (3.785 liter/gallon) = 768,476 liter of water i Advanced GeoEnvironmental,Inc.