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Table 1. Total Mass of Dissolved TPH- as Dissolved TPH-gas plume calculation summary: For the calculated volumes the TPI-gas mass range is 5000-7500 grams. V, contains a total plume mass of 4998 grains of TPH"as.---� V2 contains a total plume mass of 7496 grams of TPH-gas. A)TPH-gas area of plume with concentrations greater than 10,000 ug/L (ppb) MW-21 = 12,000 ug/L Rl =40' R2=20' A= n(10)(20) =628 ft V, =(628 f)(10 ft)(0.58) = 3,642 ft(28.317 L/ft) = 103,000 L groundwater ✓ ' V2=(628 ft)(15 ft)(0.58) = 5,463 W (28 317 L/ft)= 155,000 L groundwater 103,000 L x 12,000 ug/L = 1.238E+09 ug TPH-g= 1.238 a TPH-gas ✓ 155,000 L x 12,000 u = i 857E+09 ug TPH- = 1,857 g.TPH s ' B)TPH-gas area of plume with concentrations greater flan 1,000 ug/L (ppb) MW-20=5,040 ug/L,MW-1 =2,950 ug/L, MW-3R= 1,100 ug/L, MW-9= 1,100 ug/L, MW-2 = 1,060 ug/L, AVG=2,250 ug/IL ' Rl = 200' R2= 60' A= n(30)(100)=9420 ft lie Vi =(9420 f}2)(l0 ft)(0 58) =54,636 ft3 (28.317 L/W) = 1.547E+06 L V2=(9420 ft )(15 ft)(0 58)= 81,954 ft' (28.317 L/ft) =2.321E+06 L Note Volumes for Muter plume must have the previously calculated volume deducted ✓ ' V, = 1 547E+06 L— 103,000 L = 1.444E+06 L groundwater ✓ V2=2.321E+06 L— 155,000 L=2.166E+06 L groundwater ' 1 444E+06 L x 2,250 ug/L =3 249E+09ru,g TPH-g=3.249 a TPH-Qas 2 166E+06L x 2,250 u =4 873E+09 ug TPH7g=4&73 g TPH as C ) TPH-gas area of plume with concentrations greater than 100 ug/L (ppb) MW-17 = 346 ug/L, MW-19 =275 tig/L,AVG=310 ug/L 1 R, =240' R2= 110' 1 A= n(55)(120)=202734 f12 V, =(20,734 W)(10 ft)(0 58)= 120,200 ft3 (28 317 L/ft)=3.404E+06 L V2=(20,734 ft)(15 ft)(0 58)= 180,300 W (28 317 L/ft) =5.106E+06 L 1 V, =3.404E+06 L-- 1 547E+06 L = 1.8757E+06 L groundwater ✓ V2= 5.106E+0G L—2 321 E+06 L=2.785E+06 L groundwater 1 875E+06 L x 275 ug/L =5,106E+08 ug TPH-g=511 a TPH-gas 1 2 785E+06 L x 275 yg& =7 658E+08 ug T?H-g= 766 S TPH as 1 �''r✓GU1l��/D'Y�f 6G�, U 1 i 2 1