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Working to Restore Nature <br /> the tank cavity at 28 feet bsg Plate 8 and Plate 9 show the extent of residual hydrocarbons <br /> quantified as total petroleum hydrocarbons as gasoline (TPHg) and benzene Plate 10 <br /> shows the extent of residual benzene, toluene, ethylbenzene and xylene <br /> RESNA calculated the mass of gasoline and benzene, toluene, ethylbenzene, and total <br /> xylene isomers (BTEX) remaining to place: beneath the site using the following equations <br /> 1) Based on our interpretation, soil containing benzene remains in place between 10 to <br /> 22 feet bsg (boring BH-1) with an area affected shown on Plate 10 of approximately 183 <br /> square feet Therefore the total volume affected is approximately 2,200 cubic feet. Using <br /> 0 025 mg/kg as the average benzene concentration in the soil the total pounds of benzene <br /> (B1) were calculated as follows <br /> B1 = 0 025 mg/kg X 1x10 kg/mg X 2,200 ft3 X 123 lb/ft3 <br /> = 0 006 lb of benzene <br /> where mg = milligram, kg = kilogram, lb = pounds, ft = feet <br /> assuming the bulk density of soil = 123 lbs/ft3 <br /> • (2) Based on our interpretation, soil containing benzene remains in place between 30 to <br /> 40 feet bsg (boring BH-1) with an area affected shown on Plate 10 of approximately 180 <br /> square feet Therefore the total volume affected is approximately 1,800 cubic feet Using <br /> 0 035 mg/kg as the average benzene concentration in the soil, the total pounds of benzene <br /> (B2) were calculated as follows <br /> B2 = 0 035 mg/kg X WO-6 kg/mg X 1,800 ft3 X 123 lb/ft3 <br /> = 0 OOS lb of benzene <br /> (3) Based on our tnterpretation, soil containing toluene remains in place between 15 to <br /> 40 feet bsg (boring BH-1 and southeast corner of the tank cavity) with an area affected <br /> shown on Plate 10 of approximately 250 square feet Therefore the total volume affected <br /> is approximately 6,250 cubic feet Using 0 06 mg/kg as the average toluene concentration <br /> in the soil, the total pounds of toluene (T) were calculated as follows- <br /> T = 0 06 mg/kg X 1x1O_6 kg/mg X 6,250 ft3 X 123 lb/ft3 <br /> = 0 05 lb of toluene <br /> • 0504gtak/123009 01 4 <br />