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MASS CALCULATIONS OF <br /> EXTRACTED HYDROCARBONS (Gasoline) <br /> Chapin Bros , Inc <br /> 1766 Monte Diablo Avenue, Stockton, California <br />' The hydrocarbon mass removed during the operating period can be calculated using the following <br /> equation, M = C•Q•t <br />' where M=cumulative mass recovered (kg) <br /> C= vapor concentration (kg/m3) <br /> Q = extraction flow rate (m3/hr) <br /> ' t= operational period (hrs) <br /> ' 15 May to 16 September 1997 <br /> using C = 2,600 µg/1 = 0 0026 kg/m3 <br /> ' Q = 150 cfm (average) = 88 2 m3/hr <br /> t = 1080 hrs. (sum of known operation) <br /> ' 0 0026 . 88 2 . 1080 =247 7 kg of gasoline <br /> 247 7 kg • 2 2046 lbs/kg = 546 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0 16 gal/lbs <br /> ' 546 lbs of gal • 0 16 gal/lbs = 87.36 gallons of gasoline <br /> 1 Time Frame C Q t Gallons <br /> (�cg11)/kglm� Wft) (hours) Removed <br /> ' 6-30 to 9-30 2,60010 0026 882 1080 87 36 <br /> ' Total of 87.36 gallons of gasoline removed <br /> 1 <br />