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Mass-Volume Calculation of Dissolved Hydrocarbons <br /> Chapin Brothers, Inc <br /> ' 1766 Monte Diablo Avenue, Stockton, California <br /> Assumptions <br /> ' • A total volume of 641,602 gallons was extracted from between 30 May an 22 A 2002 <br /> g y d August <br /> based on effluent flow meter observations <br /> ' • Data collected from the influent pump and treat grab water samples were representative of <br /> general extracted ground water conditions <br /> ' One gallon of contains 3 785 liter so the volume of pi ocessed water expressed as Iiters is <br /> ' V= (641,602 gallons)(3 785 Ygal) = 2,428,463.5 liter processed water <br /> • Multiplying the volume of the processed water by the cumulative average benzene <br /> 1 concentration[(1,600 µg/1+520 µg/1+58µg/1+300 µg/I)/4+290 µg/1+32gg/1]/3 yields the <br /> approximate mass of benzene removed from pi ocess ed water <br /> MBenzene = ( 2,428,463 5 liter)(314 µg/l benzene) = 7 6 x 108µg Benzene <br /> MeenZ�,tr as gi ams 762.5 g Benzene <br /> Mse,izene as kilograms 0 76 kg Benzene <br /> A conversion factor of 2 2.05 Ib/kg can be used to convert Benzene to pounds <br /> MBenZcn,: = 0 76 kg Benzene (2 205 lb/kg) = 1.68 IN of Benzene <br /> • Multiplying the volume of the pi ocessed water by the cumulative average TPH-g <br /> concentration[(19,000+940+6800+27,000µg/1) / 4 + 700 µg/l + 2,600 µg/1] / 4 yields the <br /> approximate mass of TPH-g removed from processed water <br /> ' MTPH e= ( 2,428,463.5 liter)(6,912 µg/l TPH-g) = 1.6 x 10i0 pg TPH-g <br /> MTPH_g as gi ams 16,785 g TPH-g <br /> M,-PiI_g as kilograms 16.7 kg TPH-g <br /> A conversion factor of 2 205 lb/kg can be used to convert TPH-g to pounds <br /> MTPiI-g= 16 7 kg TPH-g (2 205 Ib/kg) = 37 lbs of TPH-g <br /> A total of 3.21 lbs of Benzene and 64 lbs of TPH-g is estimated to have been extracted since gi ound <br /> water treatment began on 02 April 2002 <br /> 1 <br /> �1 <br /> ' Advanced GeoEnvn-onmental,Inc <br /> 1 <br />