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MASS CALCULATIONS OF <br /> EXTRACTED HYDROCARBONS (Gasoline) <br /> Chapin Bros., Inc. <br /> 1766 Monte Diablo Avenue, Stockton, California <br /> The hydrocarbon mass as gasoline removed during the operating period can be calculated using the <br /> following equation: M = C•Q•t <br /> where: M = cumulative mass recovered (kg) <br /> C = vapor concentration (kg/m') <br /> Q = extraction flow rate (m'/hr) <br /> t = operational period (hrs) <br /> 01 October to 30 December 1998 <br /> using: C = 400 and 012 µg11 — 0.0002 kg/m' <br /> Q — 150 cfm average = 88.2 m'/hr <br /> t = 2150 hrs operation <br /> 0.0002 • 88.2 • 2150 = 3.53 kg of gasoline <br /> 3.53 kg • 2.2046 Ibs/kg = 7.8 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline. use 0.16 gal/lbs: <br /> 7.7 lbs of oat • 0.16 gal/lbs = 1.2 gallons of gasoline <br /> Total of 1.2 gallons of gasoline (TPH-g) were removed over the last quarter. <br /> Advanced GcoEn\'Ironmental.Inc. <br />