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Appendix B AGE-NC-Project No. 98-0520 Page 3 of 6 T2 = 3.5ftx 15ftx3ft V2 = V2 - V 1 - T2 -4 26,447 ft3 - 1,880 ft3 - 157 ft3 24,410 ft' Using 234 mg/kg as the average concentration of gasoline in the inner zone, the weight of gasoline is: V2 - typical weight of soil • average concentration of contaminant 4 24,410 ft3 • 125 lbs/ft' • 0.000234 -6 714.0 lbs of gasoline 3a) Approximate volume of soil to the boundary of the first portion of the third zone (V3a): Via= ('/3)(3.14)(53.3 ft)(73 ft)(13.8 ft) -4 56,200 ft3 3b) Approximate volume of the second portion of the third zone (V3b): V3b =(40.5 ft)(155.5 ft)(5.5 ft) -4 3 4,63 8 ft3 . The total volume of the second zone(V2)and the volume of the tank pit in the third zone(T3)should be subtracted from the overall volume to the boundary of the third zone (V3a + V3b) to get the volume of soil within the third zone of contamination (V3): T3 = 15 ft x 2 ft x 5 ft V3 = (V3a+V3b) - V2 - T3 -+ (56,200 ft3 + 34,638 ft) - 26,447 ft3 - 150 ft' -4 90,838 ft3 - 26,597 ft3 -i 64,241 ft3 Using 53.2 mg/kg as the average concentration of gasoline in the third zone,the weight of gasoline is: V3 • typical weight of soil • average concentration of contaminant -4 64,241 ft3 • 125 lbs/ft3 • 0.000053 -* 425.6 lbs of gasoline 4)Approximate volume of soil to the boundary of the fourth zone(V4): V4 = (1/3)(3.14)(89.2 ft)(95 ft)(21 ft) -4 186,258 ft3 The total volume of the third zone (V3) should be subtracted from the overall volume to the boundary of the fourth zone(V4) to get the volume of soil within the outer zone of contamination (V4). (Note: there is no portion of the tank pit in the outer zone to subtract): . V4 = V4 - V3 -+ 186,258 ft3 - 90,838 ft3 -# 95,420 ft3 Advanced GeoEnviron mental,Inc.