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la <br /> HYDROCARBON--IMPACTED SOIL <br /> VOLUME ASSUMPTIONS AND CALCULATIONS <br /> Volume of backfilled hydrocarbon-impacted soil capping ormer diesel UST excavation: <br /> p g thef <br /> The volume of soil was estimated from the over excavation backfilled area. <br />' V,,,;l = length x width x depth= 100 feet x 100 feet x 3 feet(average) z 30,000 ft3 = 1,100 yd <br /> Converting 1,100 yd' to cm3 yields approximately 8.4 x 10$ cm3. Using 1.5 g/cm3 as the weight of <br /> soil,the total weight of contaminated soil is approximately 1.26 x 109 g. <br /> Using 300 parts per million as the "average" concentration of TPH-d from samples SPCS 1 to 5 @ <br /> 4 feet bsg , the mass of diesel is: <br /> weight of soil • average concentration -4 1.26 x 109 g • 3.0 x 10'4 g = 3.7 x 105 g of TPH-d <br /> Converting grams of diesel to volume of diesel (gallons) using density of diesel to equal 0.85: <br />' 3.7 x 10' g of TPH-d -0.85g/cm3 = 4.45 x 105 cm3 <br /> 4.45 x 105 cm3 • (1 gallon_ 3,785 cm3) = 1.1 x 101 gallons of diesel <br /> Volume of unexcavated impacted soil adjacent to the former diesel UST excavation: <br /> An area of extent for this calculation was estimated from the side wall of the final over excavation <br /> to 25 feet to the west (half the distance to boring 137) and the vertical distribution of the impacted <br /> soil was estimated from the final over excavation samples, a depth of 10 feet. <br /> V5o<< = '/2 the volume of nrz x height= '/z rc x 25 feet'-x 10 feet = 9,800 ft' 362 yd3 <br /> ' Converting 362 yd' to cm3 yields approximately 2.76 x 10g cm3. Using 1.5 g/cm3 as the weight of <br /> soil, the total weight of contaminated soil is approximately 4.5 x 10$g. <br /> Using 11,000 parts per million as the "average" concentration of TPH-d from samples OX4, the <br /> mass of diesel is: <br /> weight of soil • average concentration 4 4.5 x 101 g • 1.1 x 10` g = 4.6 x 105 g of TPH-d <br /> Converting grams of diesel to volume of diesel (gallons) using density of diesel to equal 0.85: <br /> 4.6 x 106 g of TPH-d-0.85g/cm3 = 5.4 x 105 cm3 <br /> ' 5.4 x 106 cm3 • (1 gallon- 3,785 cm3) = 1.4 x 103 gallons of diesel <br /> 1 <br />