Laserfiche WebLink
MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4) and from field measurements collected during <br /> the SVE pilot test(Table 5), the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> IM=C- Q • t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q—extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br /> I <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br />' the approximate mass/volume of extracted gasoline hydrocarbons <br /> 29 June to 28 September 2001 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 1,143 ug/l <br /> g/1(07-11-01=730yg/1,08-09-01=1,200,,,g/1 and 09-13-01=1,500, avg = 1,143 E,g/11 The average flow rate <br /> was calculated at 4 2 inches of water or approximately 115 cubic feet per minute(nomograph),the operational <br /> period was equal to 2,158 hours of running time <br /> C = 1,143 gg/1=0 001 143 kg/m' <br />' Q z 4 2 inches water z 115 ft' <br /> /mm <br /> t=2,158 hours <br /> Converting Q to m'/hour yields <br /> Q=(115 ft'/min)-(60 rmn/hour) -(0 0283168m3/fe) = 195 39 m'/bour <br /> IM=C• Q - t=(0 001143 kg/m) •(195 39 m'/hour) - (2,158 hours)=481 95 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 481 95 kg of gas - 2 2046 lbs of gas/kg of gas= 1,062 5 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 1,062 5 lbs of gas - 0 16 gal of gas/lbs of gas = 170 gallons of gasoline <br /> I <br />