Laserfiche WebLink
I <br />' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br />' Assumptions <br /> • Utilizing analytical data collected from air samples (Table 4) and from field measurements collected dunDg <br />' the SVE pilot test(Table 5),the volume of extracted gasoline hydrocarbons at the site can be approxinutted <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q• t <br />' where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m`) <br /> Q=extraction flow rate(m`/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br />' the approximate mass/volume of extracted gasoline hydrocarbons <br />' 01 April to 30 June 2001 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 1,440 mgll <br /> g/1(04-12-01= 1,700gg/l,05-21-01=1,860µg/l,06-06-21=1,200,ug/l and 06-26-01 = 1,000,ag/l, avg = 1,440 <br /> l <br /> ,ug/1) The average flow rate was calculated at 3 13 inches of water or approximately 94 cubic feet per minute <br /> (nomograph),the operational period was equal to 1,836 hours of running time <br />' C = 1,367µg/l=0 0011440 kg/m` <br /> Q = 3 13 inches water = 94 ft'/mm <br /> t= 1,836 hours <br /> Converting Q to rni/hour yields <br /> Q=(94 felmin) •(60 mm/hour)•(0 0283168r0ft')= 159 71 m`/hour <br /> IM=C • Q • t=(0 001440 kg/m') •(159 71 m`/hour) • (1,836 hours)=422 25 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 422 25 kg of gas• 2 2046 lbs of gas/kg of gas=930 89 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 930 89 lbs of gas • 0 16 gal of gas/lbs of gas = 149 gallons of gasoline <br /> 0 <br /> I <br />