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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> • <br /> tAssumptions <br /> • Utilizing analytical data collected from air samples (Table 4) and from field measurements collected during <br /> the SVE pilot test(Table 5), the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> 1 <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C • Q • t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m') <br /> Q=extraction flow rate(in/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 01 January to 31 March 2001 <br /> 1) The average,analytical TPH-g concentration for this hme interval was determined to be 1,367,.ag/l The average <br /> flow rate was calculated at 2 6 inches of water or approxumtely 84 cubic feet per minute(nomograph),the <br />' operational period was equal to 1,689 hours of running time <br /> C = 1,367 Lig/l=0 001367 kg/m' <br /> Q z 2 6 inches water r 84 ft'/min <br />' t= 1,689 hours <br /> Converting Q to m3/hour yields <br />' Q=(84 W/min) •(60 mnn/hour) •(0 0283168m3/ft)= 142.72 m3/hour <br /> M=C • Q • t= (0 001367 kg/m') •(142 72 m'/hour) • (1,689 hours)= 329 52 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br /> 329 52 kg of gas • 2 2046 lbs of gas/kg of gas =726 46 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 726 46 lbs of gas • 0 16 gal of gas/lbs of gas = 116 2 gallons of gasoline <br />