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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> • <br /> Assuiriptions <br /> • Utilizing analytical data collected from air samples (Table 4) and from field measurements collected during <br /> the SVE pilot test(Table 5), the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q • t <br /> where M=cumulative mass recovered(kg) <br />' C=vapor concentration(kg/m?) <br /> Q=extraction flow rate(n'/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval was utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> I <br /> 01 October to 31 December 2000 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 1,650,ug/l The average <br /> flow rate was calculated at 3 2 inches of water or approximately 95 cubic feet per minute(nomograph),the <br /> • operational period was equal to 2,160 hours of running time <br /> C = 1,650 Mg11=0 001650 kg/m3 <br /> Q = 3 2 inches water= 45 ft'/nun <br /> t=2,160 hours <br /> Converting Q to ml/hour yields <br /> Q=(95 fe/nun) •(60 min/hour)•(0 0283168tri'Me)= 161 41 ml/hour <br /> M=C • Q • t=(0 001650 kg/rn) -(1614 in'/hour) • (2,160 hours) =575 2 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 575 2 kg of gas • 2 2046 lbs of gas/kg of gas= 1,268 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 1,268 lbs of gas • 0 16 gal of gas/lbs of gas = 203 gallons of gasoline <br />