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MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> s <br /> Assumptions <br /> • Utilizing analytical data collected from au samples (Table 4)and from field measurements collected during <br /> Ithe SVE pilot test(Table 5),the volume of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C• Q• t <br /> where M=cumulative mass recovered(kg) <br /> I C=vapor concentration(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating <br /> the approximate mass/volume of extracted gasoline hydrocarbons <br /> 31 December 2001 to 29 March 2002 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 627 ug/l g/1(01-10-02= <br /> 800 ug/l,02-18-02=560 ug/l and 03-11-02=520,avg =627 ug/1) The average flow rate was calculated at 3 1 <br /> I inches of water or approximately 95 cubic feet per minute (nomograph),the operational period was equal to <br /> 1,975 hours of running time <br /> C = 627 ug/1=0 000627 kg/m3 <br /> I Q rz 3 1 inches water= 95 ft3/min <br /> t= 1,975 hours <br /> I Converting Q to m3/hour yields <br /> I <br /> Q=(95 ft3/nun) •(60 nun/hour)-(0 0283168m'/ft') = 16141 m3/hour <br /> IM=C • Q- t=(0 000627 kg/m') •(161 41 m'/hour) • (1,975 hours)=200 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 200 kg of gas • 2 2046 lbs of gas/kg of gas=441 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 441 lbs of gas • 0 16 gal of gas/lbs of gas = 70 gallons of gasoline <br /> i <br />