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ARCHIVED REPORTS_XR0006023
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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P
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PACIFIC
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2402
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3500 - Local Oversight Program
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PR0545640
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ARCHIVED REPORTS_XR0006023
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Last modified
5/5/2020 3:13:14 PM
Creation date
5/5/2020 1:55:03 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0006023
RECORD_ID
PR0545640
PE
3528
FACILITY_ID
FA0003900
FACILITY_NAME
PACIFIC PRIDE COMMERCIAL FUEL
STREET_NUMBER
2402
STREET_NAME
PACIFIC
STREET_TYPE
AVE
City
STOCKTON
Zip
95204
APN
12506001
CURRENT_STATUS
02
SITE_LOCATION
2402 PACIFIC AVE
P_LOCATION
01
P_DISTRICT
002
QC Status
Approved
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EHD - Public
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i <br /> IMASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> IAssunzt)tions <br /> Utilizing analytical data collected from air samples(Table 4)and from field nit,asurements collected during the <br /> SVE pilot test (Table 5), the volume and mass of extracted gasoline Hydrocarbons ac the sit, can be <br /> approximated <br /> The hydrocarbon mass-volume removed during the operating 1` 11o can be calculated u5>»;the follow sog equation <br /> M=C - Q - t <br /> where M=cumulative r a-t s recovered(kg) <br /> C=vapor cone( i ation(kg/m') <br /> Q=extraction flow rate(m'/hr) <br /> t operational period(hrs) <br /> The average inlet TPH-g concentration and average#low r ates during each time zterval were 11t11zed for calculat trig the <br /> Iapproximate mass/volume of extracted gasoline hydrocarbons <br /> I22 June to 23 September 2004 <br /> 1) The average analytical TPH-g concentration for this time interval was determuied to be 768 gg/l(06/22104= <br /> 110 µg/l, 07/22/04=360 pg/l, 08/25/04= 1,200 Rg/I, 09/23/04 — 1,400 }ig/l, avg —768 gg/1) The average <br /> I flow rate was calculated at 2 0 inches of water, or approximately 73 cubic feet per mmute (nomograph),the <br /> operational period was equal to 2,232 hours of running tune(Table 6) <br /> C = 768 g.g/1=0 000768 kg/m' <br /> I Q = 2 0 inches water = 73 ft3/muI <br /> t=2,232 hours <br /> t Converting Q to m'/hour yields <br /> Q=(73 fr'/min) -(60 nun/hour) -(0 0283168m'/ft)= 124 m'/hour <br /> IM=C- Q - t=(0 000768 kg/m')•(124 m'/hour) - (2,232 hours) =212 6 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> I212 6 kg of gas - 2 2046 lbs of gas/kg of gas=468 6 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 468 6 lbs of gas - 0 16 gal of gas/lbs of gas z 75 gallons of gasoline <br /> I ' <br /> Advanced GeoEnvironmental,Inc <br />
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