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VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the volume and mass of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C• Q• t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br /> Q=extraction flow rate (m'Ihr) <br />' t=operational period(hrs) <br /> The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br />' approximate mass/volume of extracted gasoline hydrocarbons <br /> 24 March 2004 to 22 .lune 2004 <br /> 1) The average analytical TPH-g concentration for this time interval was determined to be 93 gg/I(03-24-04=50 <br /> pg/l,04-28-04= 100 pg/l, 05-26-04= 110 pg/l&06-22-04= 110 µg/1 ,avg =93 µg/1) rbe average flow rate <br />' • was calculated at 2 0 inches of water or approximately 74 cubic feet per minute(nomograph),the operational <br /> period was equal to 2,160 hours of running time(Table 6) <br />' C = 340 pg/l=0 000093 kg/m.' <br /> Q = 2 0 inches water = 74 ft' <br /> /min <br /> t=2,160 hours <br />' Converting Q to m3/hour yields <br /> Q=(74 W/min) •(60 min/hour) •(0 0283168m'/fl')— 125 7 m'lhour <br />' M=C• Q • t=(0 000093 kg/rn')•(125 7 m'/hour) • (2,160 hours)=25 25 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 25 25 kg of gas • 2 2046 lbs of gas/kg of gas=55.7 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 55 7 lbs of gas • 0 16 gal of gas/lbs of gas = 8.9 gallons of gasoline <br /> . Advanced GeoEnvironmental,Inc <br />