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MASS CALCULATIONS <br /> • The hydrocarbon mass removed durmg the operating period can be calculated using the following equation <br /> M=C•Q•t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m'fhr) <br /> t=operational period(hrs) <br /> 01 Apnl 2000 to 24 May 2000 <br /> using C=510 µg/1=0 0005 kg/m, <br /> Q= 270 cfm(average)=456 3 m3/hr <br /> t = 1295 hrs(sum of known operation) <br /> 0 0005 •270• 1295 = 175 kg of gasoline <br /> 175 kg•2 2046 lbs/kg= 385 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline,use 0 16 gal/lbs <br /> lbs of gal•0 16 gal/lbs= 62 gallons of gasoline <br /> 24 May 2000 to 17 June 2000 <br /> using C=500 µg/1=0 0005 kg/m, <br /> 1 Q= 270 cfm(average)=456 3 mi/hr <br /> • 1 ` t = 576 hrs(sum of known operation) <br /> 0 0005 •270• 576= 78 kg of gasoline <br /> 78 kg•2 2046 lbs/kg= 171 lbs of gasolme <br /> to convert lbs of gasoline to gallons of gasoline,use 0 16 gaMbs <br /> lbs of gal•0 16 gal/lbs= 27 gallons of gasoline <br /> Total of 89 gallons of gasoline removed during the operational pend <br /> • Advanced Ge*Fnvironmenta4Inc <br />