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MASS BALANCE ANALYSIS <br /> Operating Parameters: Liquid loading - 0.6 gpm (continuous) <br /> Vapor loading - g0 scfm <br /> Total Nonmethane Hydro- <br /> carbon concentration - <o.001 ppm <br /> Assumptions: 1) 100 percent transfer of contaminants to vapor <br /> phase <br /> 2) Vapor influent is not contaminated <br /> Mass Balance Equation <br /> i <br /> X . Yin)(Lin x n) + (Vin x n) _ (Lout x Xout) 4• (Vout x Yout) <br /> Where, <br /> L = Liquid Loading = 0.6 gpm <br /> X = Contaminant concentration, liquid phase = <o,0o1 mg/l <br /> V = Vapor Loading = 90 scfm <br /> -tel Y = Contaminant Concentration, vapor phase <br /> and, <br /> Yin = Xout - 0 <br /> J <br /> Simplifying then, <br /> Vout x Yout = Lin x Xin = Contaminant vapor discharge (lbs/day) <br /> j Vout x Yout = <br /> (0.6 gal/min) (<0.001 mg/1) 1 pm , x 3.7851 x _ 1 __1b x 1440 min <br /> 1000 mg gal 453.5 gm day <br /> Vout x YOut = <0.0000029 lbs/day <br /> Rearranging the mass balance equation and solving for the conc,_ntration d <br /> of nonmetha��e hydrocarbons in the vapor discharge (Yout) , <br /> Yout = Lin x ?din = 0.6al min x <0.001 m 1 <br /> vout' 9D ft /min x 7.48 gal/ft <br /> YOut = <0.0000009 mg/1 nonemethane hydrocarbons <br /> (;itrn"Im,:ui:u <br /> N.Iclixt)uw.5'.Lac. <br />