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r <br /> MASS BALANCE ANALI <br /> Operating Parameters: Liquid loading - 0.9 gpm (continuous) <br /> Vapor loading -- go scfm <br /> Total Nonmethane Hydro- <br /> carbon concentration - <O.001 ppm <br /> Assumptions, 1) loo percent transfer of contaminants to vapor <br /> phase <br /> Vapor influent is not contaminated <br /> Mass Balance Equation <br /> (Lin x Xin) t (Vin x Yin) = (Lout x Xout) {Vout x gout <br /> Where, <br /> L = Liquid Loading = o.9 gpm <br /> ! X = Contaminant concentration, liquid phase = <0.001 mg/l <br /> ' V = Vapor Loading = 90 scfm <br /> ! Y W Contaminant Concentration, vapor phase <br /> `JJ and, 1 <br /> 1 Vin = Xout = O ' <br /> f <br /> F Simplifying then, <br /> i <br /> Vout x Yout = Lin x Xin = Contaminant vapor discharge (lbs/day) <br /> 1 Vout x Yout = <br /> E <br /> (0.9 gal/min) (<0.001 mg/1) 1 am x 2.785i x 1 lb x 1440 min <br /> 1000 mg gal 453.5 gm day <br /> Vout x Yout = <0.0000011 lbs/dav <br /> Rearranging the mass balance equation and solving for the concentration <br /> Of nonmethane hydrocarbons in the vapor discharge (Pout) . <br /> Yout = Lin x Xin = 0.9 a1 min x <0.001 m 1 <br /> out 90 ft /min x 7.48 gal./ft <br /> E <br /> Yout = <0.0000011 mg/1 nonemethane hydrocarbons <br />