ARCHIVED REPORTS_XR0012640 - Laserfiche WebLink

Home Browse Search

e 3 wY California Test 301 1973 b. Gr:tvvl Hquitalent Factor ((:I) C':Ilclllatiol►s for t:emmni Trralyd Pj%v—(3,r•,C. E2 (aS't'r Mal l'f ltlh A1hh11t E'onrrolr urth I'„ml;C:r,ldes of 7/ A,pha'1 r til-'V1-An'Jalp... _. .... II-NII '. Cover%laterial includes subbase,baso,and surface ss-(.D i� courses when the basement sail is bring considered. 5-r0 21+ When the subbase material is beinr•tested,the cover �sn 14q would irtclutle only the base and surface r'ouEI rses Sim- a.�ls►a ! I :n5-ll 1 71 n CONVERSION CHART E2.- n 1 s' EWL TO TRAFFIC INDEX135-140 Is= Ihhuninonl,tiurfectns cath hrywd.ti,halt Grarlrs NO.Op.,(ir.rded Vitcs,I[r.jh. fim Al h.11l Surfenne,end flaininnoul Trrsted lSsc,•>'t elle I.y,E.�phAll r........ ... ...... ..... I n lime Ttr•.ne'.liar U, -+ t'uln'med 5,!grxt n.uec ........,._. .. I 1 'A4erer:atr If the covers consists of multi-layer construction, is °R� $ 0 8 n o the combined grnvei equivalent factor may be deter. °Qo mined from the procedure given in the falhvillg ex- .00. x- 00. 0 r4 15 ? a°o Problem: Determine the combined gravel cgiva- '- v1i lent factor for the 3-layer combination of asphalt con- 034.000.000 r3/ � %.Ovo Crete surfacing,Class-A cement treated base (C'1-11) I7 4_ and aggregate subbase (AS) material given below. 93 700.00❑ 3s000 First cairvert the individual thicknesses of asphalt tt s `6oW concrete, cement Ireated base and aggreg:lte sub- ga soflppO -� base to their respective and total gravel equivalents a° to 6 �90 (CE) by multiplying the individual thickness by the A�6o°o p� 9 3� 'o°o GI for that layer and summing as shown: IT i0 0p Q Qg ° O N �O °O° SLrtrr:rl nkInesf Cr C:E Q� AC fI°orTI a8O)............,..__................. 025' 2.01 0.511' o � $ CIS I Class A)............................................ 0.70' 1.7 1.19' vAS................................................................_ O.SIr 10 050' Tot.h............._............,........................... 1.45 F19' . . EwL vat,ues Knowing the actual thickness of the cover inn terial and having computed its gravel equivalent (2.19'), EOUATIOM determine the combined gravel equivalent factor as a El9 shown below using the above example. TRAFFIC WOE%.caE i 6'-� Gr= (Total Gravel Equivalent of Cover)i (Actual Thickness of Cover) FIGURE lb ilarly,when the base is being evalunted,cover would A second method of determining the combined mean the bituminous surface alone. gravel equivalent factor,in lieu of the above calcul;►- If the cover consists of a single layer,the oppropri- tions,is provided by use of Figure 19 as described in ate gravel equivalent factor may be solected frons the following procedure: Table 2. Conver!the thickness of each individual laver to TABLE 2 its gravel equivalent by using a straight-edge to GRAVEL EQUiVAtENT FACTORS FOR COMMON int('rsect Scales I and H at the actual thickness and PAVEMENT AND BASE MAT°RIALS' gravel equivalent L►ctor of the layer;the intersec- — . --- - - ---TlFre.4lalydstr _... _...rr __._.__Eioti-of Clio hnc�ticith Sc-ile C is the gra vel equiva- Cetrlcnl Treated A17 '7 hr.r gr;--t raprivalenl f rrlors act.17rrhrd 1`10111 Mhruinmrlrl - Ccmrnl Tee+!cd Ba:e�C]ss li......._..._...._............. .......... 1,5 and ro.rd teal rC51ri:S.F'ur further i11forlralion refer to rererena-\'o.Z - } 23