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t ..an agu .cam..,;-yb,-• ra by 4 _ -•r �. '. ,a� �. ,eya'�a.. _ �,.=y� r F Cafifornio Test 301 1978 GRAVEL EGUIVALFN- , IN FEET _ Art MWHALT':WCHPM:~ --W Ir LT(711Ftti �� ------------..- .. _. ----- -- --------- -----."- FINN . 55nc o•, tot n 5 13S 135 11111'kl h -..�i1;g Sub- Srinal I T1 14eln- 60 .0 At) 911 Ino i10 1110 130 140 Ill ft .4 II k' I il"I• liThick ItIs av (n ract.'T Feel C" ^.SO 2 72 ^_14 ''_Ol 1.',0 I.9 ]-:I _!4,l 157 1 9_' ]^_ 1 7 1 S 11 i 1 Ill 010 0:3 023 021 029 5t nls 017 i1iK G16 u. 55 kI 12 0.15 1 0;14 0.35 032 D30 039 O2! 026 015 9_4 03.1 D is 0",9 OSI 046 043 04n 039 035 034 01.1 P31 0 0:4 02,5 era 0.;.9 05. U-SO 047 045 043 (141 0 'i 035 41J 030 075 U.7D 064 067 057 U54 051 i'49 047 044 U36 0.35 089 Oil 0:3 0'0 ONi 0rZ 0w 957 0.55 053 0.42 039 1135 040 1(40 093 Oxy i14(1 Dari 072 (4;'s 0'.1. bfl it al 4144 044 1140 045 1.117 O,y9 091) Ohs OSI U77 074 11.71 0414 11.'14 0.'. 111@; 0,'.4 0511 if 15 0.50 1.16 107 IDI 09.`. W6 11 012 079 076 OrA OSS it 75 0411 OSS 41.14) 055 1.19 1.11 1.04 095 0.94 :190 0h; 0.54 fsG5 094 Ohs D6 D8t OM 060 121 1.13 1.07 103 098 094 0.91 072 102 090 0.72 066 01510 144 I 1.31 1.37 116 1.11 1.lr IM 099 0.79 1-11 079 0.:9 OTE D(is 070 132 1.1% 1.20 1 15 1.10 1,06 0.54 L19 105 0.44 077 if.70 0.75 1.34 IM 1.23 1.1.4 1.14 0.'40 1''1 1.13 0 90 0(11 13:5 0.90 1.43 137 1.31 1.26 1.1`1 0.96 L3 120 0,91, 068 0.90 - 085 1.52 145 139 1.33 129 1.0: L24 i.02 0.94 DRi 0.50 1.54 148 1.41 1.37 108 1.53 1.35 1.419 099 090 - 0.95 1.36 1.49 1.44 1.14 '.52 1.33 1.14 1 DS 0.95 100 164 1.57 1.52 1.20 1.70 1.50 '^_O 1.10 1.00 140 1.65 :.6if 1.26 1.78 1.53 i-'9 1.19 1.45 FIGURE 21 Thus,the minimum allowable structural section over Ft77mple:lnteesf!ct the sloping traffic index line:of 10 R-value basement soil for average rural highway &0 with the vertical line representing the R-value of traffic is: 10 and read the gravel equivalent of 2.3f" on the 77r1r4nicss AWerial cs horizontal line. D.30' Asphalt Concrete G. n. Select a base type for a design analysis. 0.8y Class II Aggregate Bate 0.72' 1.130' so A-aloe subbase 1.00' Example.Assume a Class A cement treated 'base. - 1.95 Total 232' 3. Determine the gravel equivalent of asphalt con- Various other structural sections which might also be crete surfacing required by intersecting the sloping used satisfactorily for the above traffic and soil condi- traffic index line with the vertical line representing Cons would be: the R-value of the base material (for aggregate base) 77,irknrss ,lfaferial CE and reading the gravel equivalent on the horizontal _ 0.2y Atplsalt concrete 0.50' line. If Class A or Class B cement tre;lted base is DSO' Class A Cement Treated Base 0$5' decided Upon, select the minimum thickness re- 0,95' Subiwe 095' 7-w 2ao. quired for the proposed surfacing from the Califor- D.s' Asphalt Concrete ate. nia Highway Design Manual. 065' Class C Cement Treated Anse 0:78' F117mple; Use 0.25' of AC surfacing over Class A - - I.l7.S' -Subbase L05' 1.95, 2a1. cement treated base for a traffic index of 8.0. G. SOLUTION OF PROBLEM BY USE OF DESIGN CHART `1- From Figure 21,find the actual thickness of as. (FIGURES 2D AND 21) phplf concrete for the gravel equivalent found in qw Step 3.For treated bases,rind the gravel equivalent This method should be used to check the results of _r the surfacing. the calculations described above or as:I quick solu- tionL:4.u77 !e.0.25'of AC surfacing a has gravel a uiva- of the design equnticn in the field. P f3 ` q 1. Determine the total gravel equivalent needed lent of 0.50'. by intersecting the sloping traffic index line with the 5. Deter nine the gravel equivalent of materials vertical line representing the R l.11ue of the base- required over the subbase by intersect"ng the sloping ment soil and reading the gravel equivalent on the traffic index line with the vertical line representing horizontal line. the R•vafue of the subbase material.