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&I Design Example Solution(Cont) <br /> Step 3 <br /> r _ 3ft(6f.-3.5ft)_ 1.25 ft. <br /> 2 - 6f <br /> Step 4 <br /> B2 =2(125ft.) =2.5 ft. <br /> Hc2 -125 Vromfrgure 2) <br /> B2- <br /> sten 5 <br /> Hc2 =2.5 ft. (1.25)=3.13 ft. <br /> 2 =Tan-1(I25frJ3.13ft.) _-21.8 <br /> Step 6 <br /> Tan01 =50 <br /> Tan02 =.40 <br /> P `73 i� 12 3_(3-3.5(-50))3 +? (3-3.5(50))3 <br /> N 50 32(5®) 32(-40) <br /> P =247 ft./ft <br /> N <br /> (12) <br />