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ARCHIVED REPORTS_XR0011933
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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WILSON
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2900 - Site Mitigation Program
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PR0541653
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ARCHIVED REPORTS_XR0011933
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Last modified
10/10/2020 10:52:06 PM
Creation date
7/9/2020 8:22:59 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0011933
RECORD_ID
PR0541653
PE
2965
FACILITY_ID
FA0023871
FACILITY_NAME
TOP FILLING STATION
STREET_NUMBER
101
Direction
S
STREET_NAME
WILSON
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15125307
CURRENT_STATUS
01
SITE_LOCATION
101 S WILSON WAY
P_LOCATION
01
QC Status
Approved
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LSauers
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EHD - Public
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APPENDIX <br /> . H <br /> SOIL VAPOR EXTRACTED VOLUME-MASS CALCULATIONS <br /> TOP FILLING STATION <br /> 101 South Wilson Way, Stockton, California <br /> Assumptions <br /> • Utilizing field measurements and analytical data collected from air samples between 08 <br /> March 2005 and 05 April 2005,the volume and mass of extracted gasoline hydrocarbons at <br />' the site can be approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the <br /> following equation <br />' M=C • Q • t <br /> where M=cumulative mass recovered (kg) <br /> C=vapor concentration (kg/m') <br /> Q= extraction flow rate (m3/hr) <br /> t= operational period(hrs) <br /> 1) 08 March 2005- 05 April 2005 <br /> The average analytical TPH-g concentration for this time interval was determined to be 5,000 µg/1 <br /> (03-08-05= 5,000 µg/1 and 04-05-05 = 5,000 µg/1, avg = 5,000 µg/1) The average flow rate was <br />' calculated at 130 inches of water or approximately 60 cubic feet per minute (nomograph), the <br /> operational period was equal to 669 hours of running time (Table 6) <br /> TPH-g (total petroleum hydrocarbons quantified as gasoline) <br /> C = 5,000 µg/1=0 005000 kg/m' <br /> IQ z 1 30 inches water = 60 ft3/mm <br /> t= 669 hours (28 days) <br /> Converting Q to m'/hour yields <br /> IQ =(60 ft/min) • (60 min/hour) • (0 0283 I68m3/ft')= 101 94 m'/hour <br /> M=C • Q • t= (0 005000 kg/m') • (101 94 m3/hour) • (669 hours)=340.9 kg of TPH-g <br /> Advanced GeoEnvironmentai,Inc <br />
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