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ARCHIVED REPORTS_XR0011934
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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WILSON
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2900 - Site Mitigation Program
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PR0541653
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ARCHIVED REPORTS_XR0011934
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Last modified
7/10/2020 4:05:21 AM
Creation date
7/9/2020 8:23:57 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0011934
RECORD_ID
PR0541653
PE
2965
FACILITY_ID
FA0023871
FACILITY_NAME
TOP FILLING STATION
STREET_NUMBER
101
Direction
S
STREET_NAME
WILSON
STREET_TYPE
WAY
City
STOCKTON
Zip
95205
APN
15125307
CURRENT_STATUS
01
SITE_LOCATION
101 S WILSON WAY
P_LOCATION
01
QC Status
Approved
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LSauers
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EHD - Public
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. APPENDIX G <br /> SOIL VAPOR EXTRACTED VOLUME-MASS CALCULATIONS <br /> TOP FILLING STATION <br /> 101 South Wilson Way, Stockton, California <br /> Assumptions <br /> • Utilizing field measurements and analytical data collected from air samples between 07 <br /> December 2005 and 14 March 2006, the volume and mass of extracted gasoline <br /> hydrocarbons at the site can be approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the <br /> following equation <br /> M= C - Q - t <br /> where M=cumulative mass recovered (kg) <br /> C =vapor concentration (kg/m') <br /> Q =extraction flow rate (m'/hr) <br /> t= operational period(hrs) <br /> i) 07 December 2005 - 04 January 2006 <br /> The average analytical TPH-g concentration for this time interval was determined to be 1,650 µg11 <br /> (12-07-05= 1,900 µg/1 and 01-04-06 = 1,400 µg/1, avg = 1,650 µg/1) The average flow rate was <br /> calculated at 2 80 inches of water or approximately 89 cubic feet per minute (nomograph), the <br /> operational period was equal to 581 hours of running time (Table 6) <br /> ITPH-g (total petroleum hydrocarbons quantified as gasoline) <br /> C = 1,650 µg/1 = 0 001650 kg/m' <br /> Q = 2 8 inches water = 89 ft' <br /> /mm <br /> t= 581 hours (24 days) <br /> Converting Q to m'/hour yields <br /> Q= (89 ft/min) - (60 min/hour) - (0 0283168m'/ft')= 151 21 m'/hour <br /> M= C • Q • t= (0 001650 kg/m') • (151 21 m'/hour) • (581 hours) = 14496 kg of TPH-g <br /> IConverting kg of TPH-g to pounds of TPH-g yields <br /> Advanced GeoEnvironmentnl,Inc <br /> I <br />
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