Laserfiche WebLink
i <br /> VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> Assumptions <br /> • Utilizing field measurements and analytical data collected from air samples between 31 August and 01 October <br /> 2004,the volume and mass of extracted gasoline hydrocarbons at the site can be approxmiated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> IM=C• Q• t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br /> Q—extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br /> 31 August- Ol October 2004 <br /> The average analytical TPH-g concentration for this time interval was determined to be 71,333 µg/1(08-31-04=98,000 <br /> µg/l, 09-22-04—81,000 µg/1, 10-01-04=35,000µgll,avg =71,333 pg/1) The average flow rate was calculated at 0 1 <br /> inches of water or approximately 18 cubic feet per minute(nomograph),the operational period was equal to 744 hours <br /> Iof running time(Table 6) <br /> 1) TPH-g(total petroleum hydrocarbons quantified as gasoline) <br /> C z 71,333 µg11—0 071333 kg/m3 <br /> Q = 0 10 inches water= 18 ft/ruin <br /> t=744 hours(31 days) <br /> Converhng Q to rn'/hour yields <br /> Q=(18 ft3/min) •(60 nun/hour) •(0 0283168m /ft)=30 58 m`/hour <br /> M=C• Q• t=(0 071333 kg/m') •(30 58 m'/hour) • (744 hours)= 1,623 kg of TPH-g <br />' Converting kg of TPH-g to pounds of TPH-g yields <br /> 1,623 kg of TPH-g • 2 2046 lbs of TPH-g/kg of TPH-g=3,578 lbs of TPH-g <br /> I <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> I3,578 lbs of gas • 0 16 gal of gas/lbs of gas = 573 gallons of gasoline <br /> I <br /> I <br /> I <br />