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1 <br /> IVOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> s - <br /> Assumptions <br /> • Utilizing field measurements and analytical data collected from air samples between 010ctober and 22 <br /> December 2004,the volume and mass of extracted gasoline hydrocarbons at the site can be approximated <br /> The hydrocarbon volume-mass removed during the operating period can be calculated using the following equation <br /> M=C- Q - t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br /> Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br /> 01 October- 22 December 2004 <br /> Tile average analytical TPH-g concentration for this time interval was determined to be 24,660µg/1(10-01-04=35,000 <br /> pg/l, 10-12-04=43,000 µg/l, 10-18-04=34,000 µg/1, 11-23-04=5,100 µg/l and 12-22-04=6,200 µg/1,avg =24,660 <br /> I µg/1) The average flow rate was calculated at 0 48 inches of water or approximately 39 cubic feet per minute <br /> (nomograph),the operational period was equal to 1,968 hours of running time(Table 6) <br /> 1) TPH-g(total petroleum hydrocarbons quantified as gasoline) <br /> C = 24,660 µg/1=0 024660 kg/m' <br /> 10 Q = 0 48 inches water z 39 fl/min <br /> t= 1,968 hours(82 days) <br /> Converting Q to m3/hour yields <br /> Q=(39 f1'/min)•(60 mui/hour)-(0 0283168m'/fl:')=66 26 rn'/hour <br /> M=C• Q -t=(0 024660 kg/m')•(66 26 m'/hour) • (1,968 hours)=3,215 kg of TPH-g <br /> I <br /> Converting kg of TPH-g to pounds of TPH-gYields <br /> 3,215 kg of TPH-g - 2 2046 lbs of TPH-g/kg of TPH-g=7,088 lbs of TPH-g <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 7,088 lbs of gas • 0 16 gal of gas/lbs of gas = 1,134 gallons of gasoline <br /> • <br /> I <br />