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' MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS CONTINUED 06 August to 16 August 1999 ' 2) The TPH-g concentration on 06 August 1999 was 370,ug/l,the TPH-g concentration on 16 August 1999 was 3,400 4g/1 The average TPH-g concentration for this time interval was calculated to be 1,885 dig/l The average flow rate was calculated at 1 09 inches of water or approximately 55 cubic feet per minute, the ' operational period was equal to 127 hours of running time C = 1,885 ,ug/l =0 001885 kg/m' ' Q = 1 09 inches water = 55 ft'/min t= 127 hours Converting Q to m'/hour yields Q=(55 ft'/min)-(60 min/hour)-(0 0283168m'/ft') =93 4 m3/houi 1 M =C - Q -t= (0 001885 kg/m3)-(93 4 ml/hour)- (127 hours)=22 37 kg of gasoline ' Converting kg of gasoline to pounds of gasoline yields 22 37 kg of gas- 2 2046 lbs of gas/kg of gas =49 3 lbs of gasoline ' Converting pounds of gasoline to gallons of gasoline yields 49 3 lbs of gas - 0 16 gal of gas/lbs of gas =7 89 gallons of gasoline ' 16 August to 20 August 1999 8) The TPH-g concentration on 16 August 1999 was 3,400,ug/l,the TPH-g concenti ation on 20 August 1999 was ' 580 ug/l The average TPH-g concentration for this time interval was calculated to be 1,990'ag/l The average flow rate was calculated at 0 83 inches of water or approximately 50 cubic feet pei imnute, the operational period was equal to 99 hours of running time C = 1,990/.�9/1 = 0 001990 kg/m' Q = 0 83 inches water N 50 ft3/min t= 99 hours Converting Q to m'/hour yields Q =(50 ft3/inin) -(60 min/hour)-(0 0283168m'/ft') = 84 95 m'/hour M =C • Q - t=(0 001990 kg/m') -(84 95 m'/hour) - (99 hours)= 16 74 kg of gasoline Converting kg of gasoline to pounds of gasoline yields 16 74 kg of gas - 2 2046 lbs of gas/kg of gas=36 90 lbs of gasoline Converting pounds of gasoline to gallons of gasoline yields 36 90 lbs of gas - 0 16 gal of gas/lbs of gas =5 9 gallons of gasoline