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Mass-Volume Calculation of D" ssolved (continued)" -_ -- <br /> Water occupies the porosity in the soil,which"is estimat d to be 35%of the soil-volume, so the total <br /> volume of water in,the saturated portion of the inner ellipsoid is approximated by: . . <br /> Vei _ (4:35)(175;929 ft3).--61.575;ft' . <br /> One cubic foot of water contains 7.48 gallons, so the°v lume of the.water in.the inner.ellipsoid is <br /> given by: <br /> Ve; _(61,575 ft3)(7.48gal/flt)=•460,582,gallons <br /> One gallon of water weighs 8.337,lbs/gal at 60°F,.so th' --mass of the water.in the inner ellipsoid.is _ <br /> -given by: <br /> M1e-:(460;582 galloris)'(8:337.11i/gal)=. ;83.9,873 lbs <br /> Multiplying M1e by:the MTBE concentratidn yields the a-proximate mass of dissolved.MTBE in the <br /> saturated portion of the.inner ellipsoid: <br /> MieMTSE (3,839,873 1bs)(0.000001) = 134 lbs MTBE <br /> Dividing M -by-the weight of one gallon:ofMTBE,:6:171bs/gallon;will yield the volume ofMTBE <br /> - dissolved:into the.ground water of the.inner ellipsoid: <br /> VieMTBE_ (MieMTBE)/6._17lb/gal),=3.8 'lbs/6.17 lbs/gal 0.62,gallons of MTBE. <br /> Advanced GeoEnvironmental,'[nc: <br />