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Nitrate Mass Balance Calculation: <br /> Treatment System Providing 75% Removal of Total Nitrogen (Nw = 6.5 mg/L-N) <br /> 1 <br /> Data Input: <br /> Concentration Rain (N b): 1.00 mg/L-N <br /> Effluent Quantity(Q): 7,083 gals/day Denitrification(d): 5.0% <br /> Effluent Stream(N„): 6.5 mg/L-N Deep Perc.of Rain(R): 5.01 in/yr <br /> Site Area(A): 14.0 Acres Waste Loading(W): 6.80 in/yr <br /> iResult: <br /> Mass Balance(N E): 4.0 mgt-N <br /> i MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 40% <br /> iEquations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft Z 1 ft (A) <br /> i6.8 in/yr(site) =7,083 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 R)x(1 site/14 acres) <br /> N,= WN dl-d)+RNI, Hantzsche Fennemore Eouation(N6 <br /> W+R <br /> 3.98 mg/L-N=((6.8 in/yr x 6.5 mg/L-N x(1-0.05))+(5.01 in/yr x 1 mg/L-N))/(6.8 in/yr+5.01 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/l)of combined effluent and rainfall percolate(3.98 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr)(6.8 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(6.5 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil (5%). <br /> R= Uniform deep percolation of rainfall (5.01 in/yr). <br /> iNb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 6.5 mg/L-N. <br /> ' 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 5%. <br /> 3. Estimated deep percolation of rainfall is 5.01 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> Y pE Rp0y <br /> i NEIL O.ANDERSON&ASSOC.,INC. <br /> ROE OINCK EN(NRSEINIXEERN9 L OMTOXI6 Z <br /> LNu%anLn.LeC1C�9YN O �` <br /> 4SS0 <br /> iPlate 6 <br />