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COMPLIANCE INFO_2019
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2300 - Underground Storage Tank Program
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PR0543574
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COMPLIANCE INFO_2019
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Entry Properties
Last modified
9/9/2020 10:47:39 AM
Creation date
9/8/2020 2:12:54 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2300 - Underground Storage Tank Program
File Section
COMPLIANCE INFO
FileName_PostFix
2019
RECORD_ID
PR0543574
PE
2351
FACILITY_ID
FA0024750
FACILITY_NAME
76 FUEL ISLAND & CARWASH
STREET_NUMBER
141
Direction
E
STREET_NAME
HARNEY
STREET_TYPE
LN
City
LODI
Zip
95240
CURRENT_STATUS
03
SITE_LOCATION
141 E HARNEY LN
QC Status
Approved
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SJGOV\gmartinez
Tags
EHD - Public
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Project Title: 76-Fuel Tanks <br /> CULLUMBER ENGINEERING Discipline:Structural <br /> Project No.:I CN1117 Originator:A.Foster Date: 4/3/2019 <br /> Component:5eismicAnalysis Checked:W.Cullumber Date:1 4/3/2019 <br /> Find Structure Period per ASCE 15.4.4 <br /> Ta=Cthn■ <br /> Ta= 0.11 sec <br /> Since T,<T„Sal=SDs Per ASCE 7-10,15.7-7 <br /> Sat= 0.61 g <br /> Find Tc per ASCE 15.7-12 <br /> Short Direction Lona Direction <br /> Tc=2Tt(D/(3.68*g*tanh(3.68*H/D)))A.5 T,=2n(D/(3.68*g*tanh(3.68*H/D)))A.5 <br /> Tc= 1.84 sec Tc= 2.21 sec <br /> Since T<<TL,Sac=1.5SD1/T, Per ASCE 7-10,15.7-10 <br /> Sac= 0.246 <br /> Determining Weights and Lateral Loading <br /> Tank Self-weight= 12,700 lb *Tank 11213 weight governs for seismic analysis <br /> Fuel Weight Yruei= 60 lb/ft' *varies byfuel type <br /> Tank capacity= 20,000 gal <br /> = 2,673.6 ft Dia,D= 10 ft <br /> Area= 78.54 ft' <br /> Fuel weight,W= 160,417.2 Ib Length= 37.77 ft <br /> Height of fluid,H= 7.5 ft <br /> Determining Total Base Shear on Tank <br /> V,=Sai*W,/(R/le) impulsive component <br /> Vc=Sa,*IeWJ1.5 convective component <br /> Wj tonh\IH/ W, _ on (13- <br /> W 1/3- W H /H / \ <br /> W—0.318Ntanh124RJ W0527Lnnh11.5811 <br /> Short Direction ` Long Direction \\\ <br /> Impulsive <br /> W,= 122,833 Ib 39,680 Ib (includes tank weight) <br /> V,= 82,133 Ib 31,742 Ib <br /> Convective (sloshing) <br /> Wt= 34,282 Ib 118,424 Ib <br /> VC= 7,028 Ib 24,278 Ib <br /> Total <br /> V=(Vi,+VC 2)1/2 (VI2+Vc2)1/2 Per ASCE 7-10,15.7.6.1,note e <br /> V= 82,433 Ib 39,963 Ib <br /> 4 <br />
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