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18 September 2020 AdvancedGeo <br /> Project No. 20-6116 AnEmployee-Owned Company <br /> Page 14 of 16 <br /> RESIDENTIAL/COMMERCIAL: <br /> IresiaentiaI = Volume rate of wastewater entering the soil averaged over the gross developed <br /> area (acres) in inches per year. The total wastewater volume is 300 gpd (existing <br /> residential systems) x 365 days of proposed operation = 300 x 365 days = 7.48 gallons <br /> per cubic foot = 14,639 cubic feet of wastewater. Does not account for evapotranspiration <br /> likely to occur. <br /> (commercial = Volume rate of wastewater entering the soil averaged over the gross <br /> developed area (acres) in inches per year. The total wastewater volume is 220 gpd <br /> (existing commercial systems) x 260 days of proposed operation = 220 x 260 days _ 7.48 <br /> gallons per cubic foot = 7,647 cubic feet of wastewater. Does not account for <br /> evapotranspiration likely to occur. <br /> NW = Total nitrogen concentration of wastewater at 45 mg/L-N based on the average <br /> discharge. Accounting for the loss of mg/L-N in the septic tank at 15% = 45-15%= 38.25 <br /> and the loss from the biomat at 10% 38.25 - 10% = 34.425 mg/L-N. <br /> d = Fraction of nitrogen concentration removed from the wastewater due to denitrification <br /> within the soil (25 percent for loamy sandy soils). <br /> R = Estimated Deep percolation / average rainfall recharge rate per year: 3.00 inches. <br /> Nb = Background nitrate-nitrogen concentration of rainfall recharge: 1.0 mg/I. The Nb is <br /> an average value determined for San Joaquin County by the EHD. <br /> EXISTING RESIDENTIAL/COMMERCIAL CALCULATIONS: <br /> Nr = I x Nw (1-d)+ R x Nb = (I+R) <br /> Assumptions: <br /> I = 166,700 gallons = 22,286 cubic feet wastewater + [(20 acres x 43,560 feet2) _ 12 <br /> inches] = 22.286 - 72,600 = 0.31 inches/year <br /> NW = 34.425 mg/L-N <br /> d = 25 percent denitrification <br /> R = 3.00 inches/year <br /> Nb = 1.0 milligram per liter <br /> Nr = [0.31 inches/year x 34.425 mg/L-N (1-0.25)] + (3.00 inches/year x 1.0 milligram per <br /> liter) + (0.31 inches/year + 3.00 inches/year) <br /> Nr = 11.00 = 3.31 = 3.32 <br /> Nr = 3.32 ppm nitrogen (NO3_N) <br />