My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
COMPLIANCE INFO_2022
EnvironmentalHealth
>
EHD Program Facility Records by Street Name
>
C
>
CHEROKEE
>
1700
>
2200 - Hazardous Waste Program
>
PR0513687
>
COMPLIANCE INFO_2022
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
11/28/2022 2:53:56 PM
Creation date
4/25/2022 9:36:55 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2200 - Hazardous Waste Program
File Section
COMPLIANCE INFO
FileName_PostFix
2022
RECORD_ID
PR0513687
PE
2228
FACILITY_ID
FA0009181
FACILITY_NAME
LODI HONDA
STREET_NUMBER
1700
Direction
S
STREET_NAME
CHEROKEE
STREET_TYPE
LN
City
LODI
Zip
95240
CURRENT_STATUS
01
SITE_LOCATION
1700 S CHEROKEE LN
P_LOCATION
02
P_DISTRICT
004
QC Status
Approved
Scanner
SJGOV\gmartinez
Tags
EHD - Public
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
92
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
View images
View plain text
Lodi Honda <br /> 1700 S. Cherokee Lane, Lodi, CA 95240 <br /> See Attachment "B" Tank Information <br /> Norma!Operation-Short) <br /> _ Wt tankfuls= 4714 Ibs <br /> Wt tank empty- 1086 Ibs <br /> 2.03 ft Wt Liquid- 3628 Ibs <br /> For VVI a �i Htank= 5.2900 ft <br /> 5.180 ft <br /> 5 790 ft governing Wta„k= 4.000 ft <br /> 2.03 ft--:> Hliquld 5.1800 ft <br /> 2.650 ft w<«re.a, hOTM= 26500 ft <br /> Armt= 2.030 ft <br /> ArmL= 2.030 ft <br /> Fp Tank Length (long)= 4.000 ft <br /> 4.00 ft Tank Width (short)= 4.000 ft <br /> FAnchor Pull Out= 0 lbs <br /> 1. Calculate Overturning & Resistina Moments 318"TrubolfWedge Anchor(2-518"min embedment) <br /> MOT = F040TM)! 2.650 xFOT <br /> OR—Wttank empty x Arm,+WtUqusd x ArmL I Fanchor x ArmA' 1,086 x 2.030+ 3,628 x 2.030+0 x 4.000 = 9,569 ft-Ibs <br /> 2. Set M = M <br /> 2.650 FOT = 9,569 <br /> FOT= 9,569 12.650 = 3,611 Ibs <br /> 3. Calculate Seismic Design Force <br /> Fp= ((0.4(ap)(SD5)(Ip)(Wp))/(Rp1Ip)) x (1+2(zlh)) Seismic Design Force (ASCE 7-16, 13.3-1) <br /> where: <br /> ap = 1.0 Wp= 4714 <br /> SIDS= 0.535 RP= 1.50 <br /> 1p= 1.5 1+2(/-/11) — 1.0 witett z is at w below file <br /> base result is 1.0 <br /> Fp (min) = 0.30 X SDS X W(tank full)X Ip Minimum Seismic Design Force (ASCE 7-16 13.3-3) <br /> Fp (min)= 0.30 x 0.535 x 4,714 x 1.50 = 1135 Ibs <br /> Fp (max) = 1.6 X SDS X W(tank full)X Ip Maximum Seismic Design Force (ASCE 7-16 13.3-2) <br /> Fp (max)= 1.6 x 0.535 x 4,714 x 1.50 = 6053 Ibs <br /> Fp = ((0.4x1.0x0.535x1.5x 4,714) 1 (1.511.5)) x (1.0) = 1513 Ibs <br /> Governing Seismic Design Force (Fp) _ Ibs <br /> 4. Calculate Safety Factor <br /> SF = Fot 1 Fp= 3,611 1 1,513 = 2.39 -Tank is Stable <br /> 5. Calculate Resistance to Sliding <br /> V < W tan 30° = 4,714 x tan 30" = 2722 > Design Force of 1513 <br /> Tank does not slide <br /> Q�aTESSio y <br /> EvtAMc <br /> Seismic/Anchoring f=indings: The tank as designed and operated, and <br /> z � <br /> the containment area in which it is located proved to be seismically sound. EXP.6I30123 <br /> ��qjE Of?C AL1 ���`� <br />
The URL can be used to link to this page
Your browser does not support the video tag.