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COMPLIANCE INFO_2022
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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2200 - Hazardous Waste Program
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PR0513687
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COMPLIANCE INFO_2022
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Last modified
11/28/2022 2:53:56 PM
Creation date
4/25/2022 9:36:55 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2200 - Hazardous Waste Program
File Section
COMPLIANCE INFO
FileName_PostFix
2022
RECORD_ID
PR0513687
PE
2228
FACILITY_ID
FA0009181
FACILITY_NAME
LODI HONDA
STREET_NUMBER
1700
Direction
S
STREET_NAME
CHEROKEE
STREET_TYPE
LN
City
LODI
Zip
95240
CURRENT_STATUS
01
SITE_LOCATION
1700 S CHEROKEE LN
P_LOCATION
02
P_DISTRICT
004
QC Status
Approved
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SJGOV\gmartinez
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EHD - Public
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Lodi Honda <br /> See Attachment "C" 1700 S. Cherokee Lane, Lodi, CA 95240 <br /> Tank Information <br /> (Normal Operation • Short <br /> -• Wt tank full= 2731Ift lbs <br /> 1.37 ftWt tank empty= 654 lbs <br /> FoT wt a^N - Wt Liquid= 2077 Ibs <br /> 3.210 ft �� + Htank= 3.4400 ft <br /> 1.37 ft_ <br /> 3.440 ft Governing Wtank= 2.750 <br /> _ <br /> 1.730 ftw4,w�-, Hllquld 3.2100 ft <br /> hOTM= 1.7300 ft <br /> Arm,= 1.370 ft <br /> F _ Armk= 1.370 ft <br /> FP - 4 Tank Length (long)= 4.5 00 ft <br /> 2.75 ft Tank Width (short)= 2.750 ft <br /> FAnchor Pull Out= 0 lbs <br /> 1. Calculate Overturning & Resisting Mornents 3/8"Trubolt Wedge Anchor(2-(i/8"min embedment) <br /> MOT = FOT(hOTee)= 1.730 XI=oT <br /> NR=Wt,ankempty xArm,+Wtuqud x Armr+ Fan0 ,x ArmA= 654 x 1.370+2,077 x 1.370 + 0 x 2.750= 3,741 <br /> 2. Set Mr,T = Mrz ft-Ibs <br /> 1.730 FOT = 3,741 <br /> FOT= 3,741 / 1.730 = 2,162 lbs <br /> 3. Calculate Seismic Design Force <br /> Fp= ((0.4(ap)(Sos)(Ip)(Wp))((Rp/Ip)) x (1+2(z1h)) Seismic Design Force (ASCE 7-16, 13.3-1) <br /> where: <br /> ap = 1.0 WP= 2731 <br /> SIDS = 0.535 Rip = 1.50 <br /> Ip= 1.5 1+2(z/h) = 1.0 when z is at or below the <br /> Fp (min) = 0.30 x SDS x W base result is 1.0 <br /> (tank full)X Ip Minimum Seismic Design Force (ASCE 7-16 13.3-3) <br /> Fp (min)= 0.30 x 0.535 x 2,731 x 1.50 = 657 lbs <br /> Fp (max) = 1.6 X SIDS X W(tank full)X 1p Maximum :ieismic Design Force (ASCE 7-16 13.3-2) <br /> Fp (max)= 1.6 x 0.535 x 2,731 x 1.50 = 3507 lbs <br /> Fp = ((0.4 x 1.0 x 0.535 x 1.5 x 2,731) / (1.5 / 1.5)) x (1.0) = 877 Ibs <br /> 4. CalcuGoverning Seismic Design Force (Fp) =EIIbs <br /> late Safetv Factor . <br /> SF = Fet / Fp = 2,162 / 877 2.47 > .5 OK - Tank is Stable <br /> 5. Calculate Resistance to Sliding <br /> V < W tan 300 = 2,731 x tan 30' ::: 1577 > Design Force of 877 <br /> Tank does not lid <br /> QtZOFEss/o <br /> FR N / <br /> _ / <br /> Seismic/Anchoring Findings: The tank as designec and operated, and 7 <br /> the containment area in which it is located proved to be seismically sound. I 6/�_ <br /> -I * EXP.- <br /> 0/23Z * <br /> ��q CIVI.I, ��? <br />
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