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DILTZGEN'S RAILROAD CURVL <br /> AND <br /> REDUCTION TABLES <br /> Opoftht,1914,by Eugene Dletxm Co..-New Yak CIO <br /> ✓r_7� . 7 �� L L � P.G T P. <br /> C <br /> S71 7 41 <br /> le <br /> f <br /> CURVE FORMULAS <br /> Edi. ." ''✓. fJGo1 � r��!,' —i �,�, / G �`.. elf, j <br /> Radius=R=3n 6/ (1)Degree of Curve=D and sin.D=x( 4 <br /> I Tangent=T=Rtan6 (3)Length of Curve=L=100J(4) <br /> Middle ordinate=M=R(1--nos• (8) =Rvers Y(6) <br /> �'-,',S /l�� .� r^r c�, Externa1=E=Tt9z -(7)=R+cos.g—R(8)—Rexsec#(9) <br /> s s l„ --f, ":5-,., Long Chord=C=2 R sin (10)O=Central Angle <br /> 9 71 /U 1 Z�111 ,5 EXPLANATION AND USE OF TABLES <br /> --Gives P. I.—Sta. 161+60.35 to find Stn. of P. C. <br /> and P4 ,42° 10' D---e 20'. From Table IV for 1 curve T- <br /> 8454.1 aadf$3J-414.49 it. From Table V correc0on=--.36 or T=.. <br /> 1—4AS6 fit.` P. C.—Sts. P.L—T-157+45.50. Also from (4) <br /> T.—Sts.P.C.+L=164+91..50. <br /> /QQ f Z S angent t►tleeta varyp <br /> (sroxhastely) diree* with <br /> Th <br /> p;#�1u1; �qubre of the distanse. us tangent offset for Sta. <br /> • above a <br /> 2.16ft.found as follows. From Table IlPtanp„ept.' <br /> ft=7.27 ft. Distanoe-15"ts.P. C.-=MZOt hence <br /> 1 16 ft Also any dist Wnee <br /> �' square of <br /> equalsximsbely)the dlsttmae from <br /> { '1M *e. Chas (54.WP+tf x+688.26)-2.16 It. <br /> I mon angle, D for 100 ft., D for b0 ft., <br /> k1° <br /> ids).31t G z 'or"de9.for 1 t.from Table <br /> afi above enrre.•..3 x 54.5 x SA�136.2' or <br /> W 36.2'fepm Table M. 'For Sta. 159 de9ac- <br /> I +80 11�+2—(�26.21,etc. <br /> '. be d indreilar mannw so'tangents Tffim <br /> s$1.87" For front'l able IV for I°curve FP-4ft6 <br /> E .. #8 .27 and from Table V oorrectlouup—.10 or <br /> 1 4s,eugpeas a�3r and E is measured and found to be <br /> A2 4Phat is Tauble IV FP-M.9 and+42=4.5 or Da <br /> 5*301. <br /> r <br />