Laserfiche WebLink
I,h ,� DIEU7:GEN'S RAILROAD CURVE <br /> /Df � a _ AND <br /> p <br /> REDUCTION' TABLES <br /> r/ 0V �� Q 4l C+bWrlsht.1914 en b9 Ev�eas Dial Co.,Now York Chy <br /> P7 CA <br /> 4 _3 42 24 <br /> CURVE FORMULAS <br /> Radius=R= (1)Degree of Curv® D and sin.K' Lo f1�1 <br /> �l rs LoC' eln. 7— Z—$N'I <br /> f 1 / / / U<! !/►-� Tangent=T=R A'_', (3)Length of Curve=L=100$(4) <br /> S� �1 L /< I/ /! ordmate— —R(1—cos. �(b) =Rvers (6)U Middle <br /> /h 1�y7 Q�dll External=E=TtanA-(7)=R=cos. R(8)=Rexaec. ,) <br /> ung Chord=C=2 R eias(10)D=Central Angle <br /> d EXPLANATION AND USE OV TABLES <br /> 84tions ven P. I.=Sta. 161+60.35 to find Sfa. of,p C. <br /> and P.T. n�62° 10' D=8°20'. From-Table IV for P carve)fa. <br /> �(t 3484.1 aad+8 414.49 ft. From Table V correction... or T= <br /> s 414.86 it. P. C.�Sta. P.I.—T=187+40.80. Also from.(or L= <br /> Y v�J�J i l JV. 744.00 and P.T.*-Sta.P.C.-j-L=164 j-91.00. <br /> Offsets,—Tangent offsets vary (approximstely) directli 'with <br /> D slid with square of the distance. Thus tangent offset or Sts. <br /> 15$on above curve is 2.16 ft.found as follows. From Table III t"VMt <br /> offset for 100 ft.=7.27 ft. Distance-158—Sta.P. C.=54 ecce. <br /> offae 21 (54 +100���16 it. Also.square of ft <br /> • i -- div.01bi tvAce the radius equals(approid! the ce`&mn <br /> tangent tt►eurve. Thus (54.50 +(2x888.2618 it. <br /> Dods. -Deflection angle=34 D for 100 ft., 3/a fl for 60 tt., <br /> " ' For o ft�Cn minutgs).3 x C x or-deft.for f ft:from Table <br /> M+ C. For 8ta. 158 of above curve+=.3 x 54.5 x 8H_.136.21 or <br /> �r — S'I&Y,or*4.50 x 54.5136.2'from Table III. 'For 86. 159 de8ec- <br /> - E BOOK 236 <br /> %der"Ilk—Miy be found in similar rAsnner to tangents. Thus <br /> above is 91.37 For from Table IV for P carve F04W.6 <br /> y...p60,6+831.27 and from Table V oorrecti ..10 or <br /> ft. Or aupixw A—Sr and E is measured and found to be <br /> — - - What is D? From Table IV E—Mg and+42-5.5 or- <br /> be <br /> f • <br /> i <br />