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- <br /> CURVE, TABLES <br /> Pttblidwd W KEUP'1rEL 83SER CO.', <br /> - - HOW TO USE CMVR:TABM. <br /> Table I. contains Tangents and Externakto a 1°curve. <br /> and <br /> to any other radius may be found nearly enough-bydividing theT <br /> Ext.opposite the given Cen le by"the •ven degree of curve. <br /> o find D <br /> -- T <br /> r - ------ -- ----- ---- --- t Deg. of Curve, having <br /> CentAngle"" r Ts�gent: <br /> e Tan.opposite the giver{Central le by the giv,,l�t aagdnt. <br /> - - - --- -- o fin De <br /> - - - d g, of Curve, having the en le'and External: <br /> - vide E:tt.o <br /> --- �pposite the given Central Angle by the�given External. <br /> To find Nat.Tan.and Nat.Ex.Seo.for any an b Table L:Tan. <br /> -- -- - - <br /> Ext.of twice the <br /> g'ven'angle divided by the radius o a P curve will <br /> the Nat.,Tan.or Nat.Es.Sec. <br /> Wanted a Curve with an Ext.of about 12 ft. Anggle <br /> • Intersectibn,or 1. P.-W 20' to the R. at Simon <br /> 542+72 <br /> ` K Ext.in Tab.'I oppost' a 23°20'=120.87 <br /> 120.87+12=10.07. Say a 10°Curve. <br /> Tan.in Tab. I opp.23°20'—1183.1 <br /> 1183.1+10=118.31. <br /> Correction for A.23'20'for a l0°.Cur.-x18 <br /> 118-31-FO-16-118.47-corrected Tangent: <br /> Ang.23'20'-23.�+10-2.3M—L.C.Y) <br /> (If corrected Ext.is required find in same wa <br /> --- 1 �3'✓ 3 -.___— fi 201941-def.forsta. 5 1.P.-sta. 542-1.72 <br /> a - <br /> 49 <br /> 49 <br /> -1.56 �Tan._ 1. •18.47 <br /> -- 7°19j,' <br /> _ B.C.-sta. 541+53.53 <br /> - - 11°4d- « « ` « � L.C.- 2 .33.33 <br /> 86.86 E.C.-Sta. 843+86.86 <br /> 100-53.53-4647X3'(def.for 1 ft.of 10°Cur.)-1$9.41'a <br /> DefJ40fi:-2" fora11TCilrvr~'.. , .. ,. ... �... <br /> I <br /> - Def.for 86.86 ft.-16 5%,fort a 10°Curve. <br /> - _ <br /> -, .., fel • <br /> - <br /> I - <br /> • f <br /> r , <br /> • .. <br />