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1L - oa --37 <br /> - -- --- - - _ CURS_ TABLE& <br /> - -- - Published bq=U "M & xasm CO. <br /> - - -- HOW TO ITS K CURVE-TABLM <br /> ------ - " Table I. contains Tangents and Externals to a 1°Curve. Tan.and <br /> j to any other radius miay,be f ound nearly enough,bydividit►g theTan. <br /> "`ZXL opposite the given Central le by the ' a degree of esuwe. <br /> �. <br /> --_ <br /> To find D � t��►ng1e " Taint: <br /> ' Deg. of Curve,having the Cea <br /> - --- °o a Tan.opposite the given C Angie by the glvv9gsnL <br /> -- -- ------ den <br /> --- --- o find D <br /> ,.. eg. of Curve, h the trsl��. External: <br /> -__-- vide Ext._apposite the given Central Angle by the given External. <br /> To find Nat.Tan.sad Idat.Ex.Sec.for any e Table I.:Tan. <br /> Ext.or twice the given stn leAvided by the us s 1°curve will <br /> -- - -- - - - -- be the Nat.Tan.or Nat.Ex.See; <br /> Y.: <br /> B&AXPLB. <br /> _ Wanted a Curve with an Est.of 4out 12 ft.An* <br /> - of Intersection: or I. P.-9$° 20! to the A. at Station <br /> 542-1-72. <br /> - Ext.in Tab. I opposite 230 20'=120.87 <br /> 120.87+12=10.'07. <br /> Say a 10°Curve. <br /> -. - - -: - -- - ----- Tan.in Tab. I opp.23°20'x 11 A <br /> 1183.1+18418.317 <br /> �118.31.. <br /> ------- Correction-for A.230 20'for a 10°Cur.-0.14 <br /> 4 P 118.31+0.16=118.47.-corrected Tangent. <br /> - — (If corrected Ext.is required find in same way) <br /> Ang.23°20'=23.33 +10=2.3333-L.C. <br /> 2"19}'-def.for eta. M I.P.-sta. 642-}.72 <br /> +50 Tan.m 1 .13.47 <br /> 70 19j1— <br /> j - - <br /> 9°49}'a « « -F50 B.G.-sta. 541+58.53 <br /> - - - — - - 110 qp•= « « « 543+ L.C.- 2 .33.33 <br /> 86.86 E.C.=Sta. 543-1-86.86 <br /> 100-53.53=46A7XW(def.for 1 ft.of 10°Cur.)=139.41'= <br /> - --- - -- - -- ---— 20 19}'aides for ata.542. <br /> Def.for'W ft s'r W'tdr a 10°Curve. <br /> Def.for 36A ft.r1° <br /> 5i1}'fora 10"Curve. <br /> -------- ,fir - _.. <br />