Laserfiche WebLink
1 <br /> CURVE TABLES. <br /> Pn>>*ed by M&UnML amom co. <br /> — -- -- - - _ - - - - -- How To USE CMVZ TAIRM. <br /> 7 Q Table I. contains Tan�eato and Externals to a P curve. Tan.and <br /> _—_-- - tosnyotberradiusmaybefound nearly enough,bydividingtheTan. i. <br /> y f 9 o i Ext.opposite the given Central�e by-the wren degree of curve. <br /> - -------- -- - --- To find Deg. of Curve, havin tie CentrgtAngle aid,Tangent: <br /> z> 'vide Tan.opposite the given CentralA�,�le by the given angenL <br /> To find Deg. of Curve, having the Central Az*le-&M External: <br /> Me Eat. opposite the g�'ven Central Angle by the given External. <br /> To find Nat.Tan.and Nat.Ex.See,for anya�Is b Table I.:Tan. <br /> Ext of twice the g�'ven le divided by the radius of s 1°curve will <br /> " be the Nat.Tan.or Nat Es.Sec. <br /> EXAMPLE. <br /> Wanted a Curve with an Ext.of about 12 ft. AnFle <br /> of Intersection or I• P.=23a 20' to the R. at Station <br /> -- - - - - -- - 542+72. <br /> Ext.in Tab. I opposite 230 20•=120.87 <br /> 120.87+12-10.07. Say a 10•Curve. <br /> Tan.in Tab. I opp.23°20'=1183.1 <br /> 1183.1+10=118.31. <br /> Correction for A.23°20'for a 10°Cur.-0.16 <br /> 11.8.31+0.16-118.47-corrected Tangent. <br /> -.--_ ---- (If corrected Ext,is required find in same way) <br /> Ang.23°,20'=23.33 +10=2.3333-L.C. ' <br /> 2°19}'-def.for sta. 542 I. P-sta. 542+72 <br /> V 49}'as " a « +5U Tan.- 1 .18.47 <br /> - - 7°1911- « 50 B.C.-sta. 541+53.53 r <br /> 9°49j'- a Of a +50 <br /> 110 40'- a a a 543+ L.C. 2 .33.33 <br /> 88.86 E.C.-Sta. 543+86.86 " <br /> 100-53.53-46.47x3'(def.for 1 ft.of 10°Cur.)-139.41'= <br /> .20 19}'=def,for sta.542. <br /> Def.for 50 ft.=20 30'for a 10°Curve. <br /> -- ---- - -- -- -- - ------ - --- - --- Def.for 36.86 ft.-P 50}'for a 10°Curve. <br /> IL <br /> - _ • <br /> 10'aures <br /> ----------- <br /> ' s <br /> • <br />