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BOOK 392
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BOOK 392
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1/26/2016 5:47:51 PM
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r <br /> z <br /> Tit <br /> _ <br /> -CURVE TABLES. <br /> a.LL.�L� CE Ry CO. <br /> 'f I ` r✓"I r c- ~� - /�6 t/ P40�11 ied by.AL f; +�M�' _ +Y _ -\ <br /> TO 1 SK '" � �. <br /> HOW <br /> 7 <br /> 7 `3 <br /> Table L contains Tants an�l'Eztwnals to a 10 curve. Tan: <br /> '' -. -_ _- 'ext..to any other radius may be t nearly enough,bydividing the- aa. <br /> ilrtFxt.opposite the glean Cen�.��n�la byr'the iven degess�eve. j <br /> To$nd Deg. of Curve,bavft the Caen An&a Tangent: <br /> - - - -- - --- ���-_ --- I <br /> Divide an.opposite the given Cefttral ie by the given TangmL <br /> To find Dog. of Curve, havingt)�he Central AaB,le and i xternal: <br /> _- _ -_ _ -------_--_- —_-- —-s-- -_.---_-- wide Ext.opposite the given Central Angle`by the given External. <br /> To Sad Nat.Tan.and Nat Ea.Sec.for any. le by-Table I.:Tan. <br /> Fact.of twice the 'ven angle divided by the radius of a 19 curve will <br /> the Nat.Tar.or at.Ex.Sec. <br /> f lir, z- i <br /> _ _. _✓__ _ _-- __-_ _ Wanted a Curve with'aa23'-� of a{boutt 12"ft��lng <br /> k. <br /> of Intersection or i. P.•mto the.1t. at <br /> 542-1-72. <br /> x j!, Ext..in Tab. I opposite 230 20'=1267. <br /> 120.87:12=10.07. Say a10'Curve. <br /> t Tan.in Tab. I oppp.23°20'=1183.1 <br /> 1183.1410=118.31. <br /> Correction for A.23`W-for a 19',Cur.-M14 <br /> 117. 73 (If correcOed Ext.is"6e Ared find ip satne way) <br /> - - <br /> Ang.2$°20'=23:33 +10=2.3333=L.C. <br /> Alf 1".fir' ''` _l3!.� __ � 2°19}'-def.for sta. 542 I. P.-sta. 542♦72 <br /> V 491 .= « « a -1-50 Tan.- 1 J8.47:.. <br /> --i/•� / C iC CY 1 r 1-• /'rr l T/ h. -. 70 19j'- <br /> B.C.ssta. 54i-1.53.53 <br /> 9°Y 491'=11°40' C'" 2 .33-M <br /> � <br /> L. <br /> 88.86 E.C.-Sia. <br /> 100-53.53-46.47X3'(def.for 1 it.of 106 Cur.) 139AF m <br /> 2°101'-def.for sta.542. <br /> g - Def.for 50 ft.=2'30'fora 10'Curve. <br /> Zf <br /> Def.for 36.86 ft.-1°WY for a 10'Curve. <br /> ,r,,,, s <br /> io•Gwaa <br /> I <br /> � 0 <br />
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