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p <br /> _-� <br /> fZ <br /> a <br /> b <br /> Obli,jie ruo yo <br /> /° G' j -'- i!•�J.. - f Right Trim .S ,r <br /> r , t�r -�- s _ For ,tan= b,cot ffi --.,rec±_ °-b, con"A <br /> I p•G �_o a !,8 G a 1 <br /> z >— �/2, t 1? f�_r /' s 'T =b= cot B, <br /> , <br /> /AY" + Y a <br /> a =cosB.b=V0 .d:,.c-a =0 �' <br /> °-d•,b =a cotA,a.*- a <br /> 2 <br /> On <br /> A. <br /> -A,a= b tan A,a- b <br /> cos A. <br /> 7 °-A,a =c sin A,b m a cos A, <br /> w <br /> iw :,of Oblique Tristn�gjea <br /> s- <br /> �;?ss' -- j�D l/ 1 `` �,J*it' �, #n A' C= 180°—(A { B),c=' sin <br /> r �� ¢� D <br /> -s-;z4 / Z ZED U l 3 t/ 7 G e� b sin ASC= 180°-(A+B),o a era..0• <br /> s- o2- <br /> a sinA <br /> ° p z.6 Sa 1 <br /> :-k AB=1800-C,tan (A-B)=(a-b)tan}(A <br /> a I b <br /> 1 J Z <br /> a sin C <br /> sin A <br /> i o,G fa+b-}-a I <br /> 3, C a= 2 ,sin jA=N b o ' <br /> -- / sm2B- ,C-180°-{ i A * <br /> �- -I .I,, g= +2+ , area = s s-a a- s--c i <br /> !3 o basin A <br /> a area = - <br /> i 2 <br /> _as sin B sin 0 <br /> 9 <br /> area 2 sin A . <br /> s•s c r' <br /> 7, 4' o c , REDUCTION TO HORIZONTAL 4 <br /> 41 0. i Horizontal distance-Slope distance multipliedliY <br /> p. z ?e , J cosine of the` vertical angle:Thus:slope distance <br /> q Vert angle=b 10 From Table,Page IX.oos 6 u 91169. Horizontal distance=319,4X.9068=31S.Ogft <br /> 7 i _ �1�_ Horizontal distance also=Slope distance mittus• �{ _ distance times (i-cosine of vertical angle). Witi1 e ." <br /> same figures as in the preceding example,the follow <br /> ing result is obtained.Cosine 6°10W�8060.;c8866=.OQL3. <br /> 318:�1X.U0�11=1 X 819.4-1.31=31SA01t <br /> /. / .S'__ -- - -4- falmol�m,the horizpntal distance is approzimatel tLie dist <br /> Of tbrigdse divided bq twice the slope d•itanee., aa =14 <br /> /� to S r3iitsontalE .14 X!t <br /> 44 <br /> - 2X ' <br /> • , i . - <br /> Is <br /> e <br /> i <br />