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<br /> '$1ti�ONOMETRIC FORMULAE
<br /> ��9 o
<br /> z 71 s2,i77
<br /> -� a
<br /> C
<br /> e,1-77 _ �7/ `Right eagle a Oblique Triangles
<br /> d /4 3 Solutieft of Right Triangles
<br /> 7/ �- 9" - -
<br /> i a b g
<br /> f o , :, G s/ f• 5`G J 3 3 For Angle sin = ,cw= ,tan= a cot = - e e
<br /> a 7 9 e c b b see=-, cosec=
<br /> 3
<br /> - °-7 d q.703 r_ Given aired a b
<br /> 7i s/.s 3i '�,zL� 3rY8/ a, b . ,o tan' .4 cotB,a = a$ Z
<br /> �/-}T' - a 1+—
<br /> 21/ 38. �7G ae
<br /> sSv 65,39 t 3703 Tt6,73t g,70 a- ay c , $, b si;A- - a
<br /> '3-S7f ��J97 ?81y eosB,b=� ,+ e-a =e 1-e=
<br /> /`n ! 9% B'-W-A,b =a cotA o= a
<br /> r -s.s97 ?- t' 3DB d b c
<br /> 7L•/ 0 4- . .-s. 7� .r�.{93 - 9.4�y_ 3T.J79 _ .� sin A.
<br /> 6.317. x.,.�s � a : ; p¢•S/8 65� Aub ° b
<br /> ------- ?9Z! SL11r + 5.337 _ �z3� a, a B=90�,a = bt9nA,o=
<br /> 7 7 6 --- cos A.
<br /> 5 ti so, s d- r,G 7 5 A,c a b B-9V-A, =c cosA,
<br /> y-s,000 � __�..� -- a � .a gcsinA,b '
<br /> _ S,69 c 36.69 6 Solution of Obli ue Triangles I
<br /> ti7� r = r 9�p f�1• SG ��Gf3 aired
<br /> X6.63 3 x/.333 b , = 1801-(A+B), c= asin C
<br /> a, C C
<br /> sid t1
<br /> �. �; z y•boy si n2- - y-97� �6s/y �'g .c, C sin B= ,C= 1800—(Ai-B)�o - asinC
<br /> a sin A.
<br /> A+B=1800-C tan 3(A-B -(a`-b)tan
<br /> a
<br /> 3/ S a sin)C '
<br /> � / a b
<br /> S2,f/3 �szs� �-F c sin
<br /> --- -
<br /> -_
<br /> JsoLs a b+o
<br /> a-c
<br /> .,� j• 35
<br /> 0 4 !e7 X442. t�f_7P9 - goo gyp_ 3 , �' s= +2 ,sin;A= Ise
<br /> - Y(
<br /> 64•s S / y 9,06 3 S %' r x76
<br /> T.7 0 3�9 sin 2B=
<br /> J(8-aa c C °-(
<br /> a
<br /> 8 h, - r 3 9 �_3 1 0¢ s.2 . - Ai B)
<br /> 6829s - ss•s7f t ,iso 90•/ a+b+o
<br /> meq-.2 5 6 8= 2 , area
<br /> 6-1 - bosin A a e*
<br /> 9?3 area = 2 a
<br /> 7 j9 o _a,sin B sin a
<br /> i
<br /> area - 2sin A fP .
<br /> ✓v y, - sa 6 4,¢/ DUCTI TO HORIZONT
<br /> t3.�9 QN
<br /> Horizontal distance-Slope distanceul�JX
<br /> d y t
<br /> cosineoftbeverdealangle TLus:sloDeg 4
<br /> y- S3, _ G•!3/ -- Vert;angle-B°10'. From Table,Page lw=
<br /> ---- a, r H•rizontal distance=319.4X.9969=818.99 it."
<br /> 6�•Hq - z - y•7 7 ?- � $10 1e Horizontal distance also=Slope d'
<br /> o r31 L� s�.y -o star4e times(1-cosine at veeHoala�1Wemj t$O `
<br /> • 9 o t . P w s 2 6 `�''/�- 6 3 4 1 7 2 aa�•figures as in the reeedm exam"
<br /> Hortz ing result is obtained.Cosine 501 W=:99�q
<br /> �35zS 19
<br /> 4 j
<br /> are- 4���-- �--- 3 ftrl=1=1.31,319.4-1.31 31&99 it '
<br /> �t o 0 0 O/ ¢ 4 _ ! o - 8-3 7 -. When known the Yo -
<br /> __ 7/ `; 9O '7d 1, anoe less of the rlse divid3 d by theta the is&Pe d►sdw -the, slope
<br /> °e i4 tt.,
<br /> 6. 3 0 ' - 31 2 - z / * r rF Z slope dist nth s 14 x 1
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<br /> r
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<br /> r
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