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Q o 5 3 o �y ,� - 7. - 41GONgMETRIC.FORMULAE <br /> y - - `� �` <br /> a f G 5 <br /> Ca <br /> C a� <br /> � t le Oblique Triangles <br /> ���/ �Lf� 4 96itstAon of `Right Triangles <br /> - a b a b o <br /> j G/ l 7 4 For Angl eln °_-,cog= ,tan= ,cot = ,sec=-, cosec= o <br /> a <br /> (liven 417 . <br /> b ,O . Uu►A=b= cot B,c = a -�- =a a <br /> pof4c a, a ,b sinA-Q -cosB,b=,/ O+a o-a -0 1-ate <br /> Zg, ,�40 , <br /> x-90° :s4,b -acotA,o= sin d. /k1.AW90°-A,a = b tan A,o= b .5177& `,L- ? <br /> 16 / �W-A,a=a sin A,b=a cos A, it 4,C <br /> 3 0 b of ObliqueTriangle <br /> 'A � s <br /> of 7 �e7" a !` <br /> *tin B, �,= 180°-(A + B) B-a sin O <br /> y aid A sin A <br /> _ a <br /> g j, i t vv i q.r 3 - $ $s b sa A,C= 180°—(A+B),a= sin A <br /> A+,8=1800--C,tan (A—B)=(a—b)tan j(A+:E) <br /> m _asin C a+ b <br /> sin A <br /> a+ +e <br /> 2 ,sin jA=�� b a <br /> 0' G <br /> aXs— <br /> C= <br /> 180 A <br /> B <br /> , area = s(&--a o- s-a <br /> - -- - - 5 a bcsin A <br /> / lr` +� I"Thr: ergs = <br /> o �1 a$sin B sin C <br /> area = 2 sin A <br /> 19 ►.,#,, I ' 4 REDUCTION TO HORIZONTAL <br /> V L. Horizontal distance=slope distanoe multipli y the <br /> �Y 4 ?7 /f cosine of theverticalangle.Thus:slopedistaw 4ft•: <br /> Vertangle=b°llY�.SCtope Tsb1s:Pyr eoa Oft.; <br /> r 9869 Ho ontsl di�a�oe=319.4X.9�H 06 tt <br /> j91== <br /> i nt distanoe Slope distance minas sto <br /> .` <br /> e times <br /> of vertieal m r>. with t$y <br /> - seats fish as in the d}a ez the follovrw " <br /> Is obtained.Cos ae rlW- 6 1 -.8060-.6011. <br /> E19.4JC Ll,g1 1 4r-3. t �y 4 <br /> klwwn,the al vice the is al► �tai fheris De dist- <br /> the rise <br /> by twice the slope= us: a=14 ft.. <br /> ltd didt nos-!d`l6-+S x fL <br /> 77 <br /> MW is U.s.a <br /> MOP. <br /> j . <br /> t <br /> , <br /> V <br /> • <br /> T <br /> 0 I <br />