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� <br /> PZ-1 7 <br /> CURVE TABLES, <br /> �6 Z <br /> --- r_/c.4 9 ;j s 3 — Published <br /> by KEUFFEL & ESSER Co. <br /> HOW TO USE CURVE VE TABLES. <br /> r/r G v 7)--7 Table 1. contains Tangents and Externals to a 10 curve. Tan.and <br /> or Ext o y other radius my be found nearly enough,by dividing the Tan. <br /> j ,r L PPosite the given Central An le by the iven d <br /> 7, To find Deg. of Curve, g g degree of curve. <br /> •� Divide Tan.ohang the Central Angle and Tangent: <br /> . id find. PPowte the given Central An le by the given Tangent, <br /> / 7. ]deg. of Curve, having the Cen <br /> — Divide 8 tral Angle I <br /> Ex e <br /> Ext. opposite the given Central Angle by the given Exteernall..�� <br /> y 3; JJ To find Nat.T dx. y <br /> - — or Ext of twice the v n angle divided by the any <br /> adius of a 1 Table <br /> curvee Will <br /> See.for 3 y3 I be the Nat Tan.or Nat,Ea.Sec. <br /> .; - <br /> yti> EXAMPLE. <br /> - Wanted a Curve with an Ext,of about 12 ft. Anile <br /> " y y of Intersection or L p,-239 <br /> 201--- - <br /> to the R. at Station <br /> 542+72. <br /> ti z L Ext.in Tab. I opposite 230 20'=120,87 <br /> 120.87+12=10.07. Say a 10°Curve. <br /> Tan.in Tab. I opp.230 20'=1183.1 <br /> —�•-.- <br /> 1183.1+10-118.31. <br /> y, <br /> Correction for A.23°20'for a 10°Cur.=0.16 <br /> 118.31+0.16=118.47-corrected Tangent. <br /> / 1 (If corrected Ext.is r uired find in same way) <br /> r, y� g 23.33 +10=2.3333=L.C. <br /> 3 20 19}'=def.forsta. 542 I. P.=sta. 542+72 <br /> e y 40 4911= a a a <br /> +50 <br /> 17/ 70 1911- a a a Tan.= 1 ..18.47 <br /> —1- 9°491,'= a a a +50 B. C.=sta• 541+53.53 <br /> - 110401= a a a. 543+ L.C.= 2 .33.33 <br /> - <br /> 3 7,7 86.86 E. C.=Sta. 543+86.86 <br /> 100-53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.411= <br /> ?r L _ 2°19F=def,for sta.542. <br /> 7 ' Def.for 50 ft.=20 30'for a 10°Curve. <br /> Def.for 36.86 ft.=10 501'for a 10°Curve. <br /> �99.R� � r.P.An9.23•PO• <br /> /I <br /> F'- <br /> r a >I l0•Curve <br /> y D , r ;Oi ire <br />