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-- - ,s 3- 7 r ,, - z CURVE TABLES. S" <br /> Iry R � 3 ,-� 3v/ <br /> r . <br /> -27 p t'7_'_3 -7'4 /JO 3 "`�; 3 Z � Published by KEUFFEL & ESSER COQ------ y- <br /> 1 ;r , v 7 �. _ - - ' 7 HOW TO USE CURVE TABLES 7/ <br /> ff-7- <br /> --' 77 .7 <br /> ' 77 1 } i 9 -{ 3 a Table I. contains Tangents and Externals to a 1°curve. TAn.and <br /> .4 f 3,v - - Ext,to any other radius maybe found nearly enough,bydividing the Tan. <br /> 7-7S- r 7 , 3"� y 7-b f° 7 or Ext.opposite the given Central Angle by the given degree of curve. <br /> --7/-�z- ,�y/ 7z G-- .S ?� To find Deg. of Curve, having the Central Angle and Tangent: <br /> n 3 3 Divide Tan.opposite the given Central Angle by the given Tangent. <br /> 3 3 To find Deg. of Curve, having the Central Angle and External: <br /> i. G <br /> -70 7 _ Divide Ext.opposite the given Central Angle by the given External. <br /> 3 / v - To find Nat.Ta4i:and Nat.Ex.Sec.for any angle by Table I.:Tan. <br /> 7 or Eat.of twice thegiven angle divided by the radius of a 1°curve will <br /> be the Nat.Tan.or Nat,Ex.Sec. <br /> G .7 g 3 c / y tt e v 7 —k ? / i� EXAMPLE. <br /> �� - - 7 3 S f 7 t- yr/p--- - - ! l 1t�anted a Curve with an Ext.of about 12 ft. Angle <br /> 'o Int 2 ction or I. P.=23° 20' to the R. at Station 7 L f <br /> 3 x 7 -yv 5 7 I, 7 p f J Ext.in Tab. I opposite 23°20'=120.87 36 <br /> -- <br /> S J_ 7/ 4 / a g 3 8- 7 G, 1 J 120.87=12=10.07. Say a 10°Curve. t 7 <br /> 7 3 r 7 _ 2. t` S . -;41 Tan,in Tab. I opp.23°20'=1183.1 f <br /> 7 _ _?' - _ 7- 1183.1=10-118.31. <br /> 7 4,' J Correction for A.23°20'for a 10°Cur.=0.16 <br /> t. <br /> 8.47(If corrected Ext is <br /> aired find in same way) <br /> Ang.23°20'=23.33 1-10=2.3333=L.C. <br /> �G `j�y 71-• L,�" - 7 2°19j'=def.for sta. 542 I. P.=sta. 542+72 <br /> _—�• _ y / ( r' 3 L '1 ► 3 '� <br /> 404911= cc ° a +50 Tan.= 1 .18.47 <br /> 91 - 73 - �� 7�dV7_ 7°19}'= a a a 543 <br /> r 7 [/ "�f• ? 9°49}x_ a a a +50 B. C.=sta. 541+53.53 <br /> 3 11°40'= a a a 5u+ L.C.= 2 .33.33 u . 7 <br /> - 86.86 E.C.=Sta. 543+86.86 <br /> S `/ ? �j."•° 3 / 3, 100-53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.41'= <br /> g <br /> 2 19}'= <br /> s -def.for sta.542. <br /> g x "Z y 1- Lf 6 6 7 v - Def.for 50 ft.=2°30'for a 10°Curve. <br /> 7___ _ I- n� 3 y P `-� �' _ _ Def.for 36.86 ft.=1°501'fora 10°Curve. <br /> r l s '1 017 g 7 <br /> w a Axl P.An9.23•PO <br /> �l,__7.1-''' ,e ' a <br /> -3 <br /> /y 1o•Curve <br /> l <br /> —I <br /> µ <br />