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CURVE TABLES. <br /> 94 14 Published by KEUFFEL & FZMR CO. <br /> ---- --- <br /> -7,-7., 9 v L 7 <br /> HOW TO USE CURVE TABLES. <br /> Table I. contains Tangents and Exfertials to a 1°curve. Tan.and <br /> nearly other Ext.to any oer radius maybe found <br /> - - Y y en ough,bydividing the Tan. <br /> or Ext.opposite the given CentralAngle by thegIven degree of curve. <br /> - To find Deg. of Curve, havingthe Central Angle <br /> le and Tangent: j <br /> Divide Tan.opposite the giveir Central Angle by the given Tangent. <br /> eg. of Curve <br /> y. , <br /> To find D having the Central Angle and External:, <br /> J _ Divide Ext._opposite the given Central Angle by the given External. <br /> __ _ To find Nat.Tan.and Nat.Ex.Sec.for any angle by Table I.:Tan. <br /> ' or Ext.of twice the given angle divided by the radius of a 1°curve will <br /> f "39 S" 7 $ be the Nat.Tan.or Nat.Ex:Sec. <br /> s_ EXAMPLE. <br /> Wanted a Curve with an Ext.of about 12 ft. An <br /> �3 3 <br /> of Intersection or 1. P.=23° 20' to the R. at Station <br /> - 542+72. <br /> y+ Ext.in Tab. I opposite 23°2o-=120.87 <br /> o <br /> Curve- <br /> ' n ab I ip_23 �1� <br /> Tan. <br /> a .i <br /> 118.31. <br /> -- / Correction for A.23°20'for a 10°Cur.=0.16 <br /> L L 118.31-}-0.16=118.47-corrected Tangent. <br /> _ 3 7 — . (If corrected Ext.is required find in same way) <br /> Ang.23°20'=23.33 +10=2.3333=L.C. <br /> 2°19j'=def.for sta. 542 I. P.-sta. 542+72 <br /> y 4°49}'_ a a a +50 Tan.= 1 18.47 <br /> Cf 3 70 19j'= a a " 543 <br /> 9*4911 a a a B.C.=stn. 541+53.53 <br /> ° , a a a + L.C.= 2 .33.33 <br /> 11 40'= <br /> 86.86 E.C.-Sta. 543+86.86 <br /> 6 100-53.53=46.47X3'(def.for 1 ft.of 10°Cur.)=139.431= <br /> 2°19j'-def.for sta.542. <br /> 'r Def.for 50 ft.=2°W for a 10°Curve. <br /> - ' Def,for 36.86 ft.=1°50V for a 10°Curve. <br /> --- 3 I.P.An9.23•201 <br /> �\s° - <br /> I0•cur" <br /> I <br />