Laserfiche WebLink
F1 Lo 00 47 <br /> 17 _ CURVE TABLES. <br /> - r a 3 703 3 Published by KEUFFEL do RSMR 'COQ. <br /> HOW TO USE CIJ$VE=TABLX& <br /> Table I. contains Taogenta and Externals to a P curve. Tan.and <br /> r a t.to any other radivaMy be found nearly enough,bydividing the Tau... <br /> Ext.opposite the tinea Central Ata�le b the ven dem of curve. <br /> To find Deg. of Cnrve,having the t Angle snd Tangent: <br /> vide Tan.opposite the gives Centtial Ate by the given Tangent. <br /> To find Deg. of Curve, ha the enti g Angle and Zxternal: <br /> J ivide Eat.opposite the gt'ven Cen 'Angle by'the given External. <br /> To find Nat.Tau.qnd Nat.Ithc.See.for any an by Table I.:Tan. <br /> Ext.of twice the g vea angle divided by the radius of a 10 curve"vvin <br /> S the Nat.Tan.or Nat.Ex.8me d <br /> S%AMPLE. <br /> Wanted a Curve with an Ext.of about 12 ft. Angle <br /> of Intersection or I. P.=230 20' to the R. at Station <br /> Ct - 542+72. <br /> Ext.in Tab. I opposite 23°20'—120.87 <br /> 120.87-i-12=10.07. Say a 10°Curve. <br /> Tan.in Tab. I opp.230 2(Y=1183.1 <br /> 1183.1+10-118.31. <br /> Correction for A.23°20'for a 10°Cur.—Q16 <br /> 118.31+0.16=118.47=corrected Tangent. <br /> (If corrected Ext.isuired find in same way) <br /> Ang.23°20'=23.3=10=2.3333=L.C. <br /> 2°191'=def.for sta. 542 I. P.=sta. 542+72 <br /> 4°49}'= a a a +50 Tan.= 1 .18.47 <br /> j 70 19F= a a a <br /> 543 <br /> f 90 49F= a a a +50B.C.—so. 541+53.53 <br /> 11°40'= a a a 543+ L.C.= 2 .33.33 <br /> 86.86 E.C.=Sta. 543+86.86 <br /> 100-53.53=46.47X3'(def.for i ft.of 10°Cur.)=139.41'= <br /> 2°19}'=def.for sta.542. <br /> Def.for 50 ft.=2°30'for a 10°Curve. <br /> Def,for 36.86 ft.—P 50}'for a 10'Curve. <br /> 4*a <br /> 1o•curio <br /> Ar <br /> i <br /> • <br />