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/ <br /> `4574 <br /> I c 'a _~ TRArIG Fit4=7— <br /> max ' '. <br /> U <br /> 1-5 3 r-� 3 ? a }' git Tdaeille • , 3. <br /> _ 9 .7 saw :- -,- <br /> 8 f For Mite A. sin=o,coq-7"tan�• B*4*t#* ,sec- .+bows:• ' <br /> ,✓� . Y` flivba Required s <br /> �C ,L y6 b d,B,c tan d b=cflt B,o V10 + as <br /> /o , •� y . <br /> 1" Z 6 d, B,b sinal a saeosB.b,- o-Fa o :4r-o. 1-;s <br /> s- <br /> ds a B, b, 6 BsWs+d,b amtd,e® Birt d. <br /> y9 sy b <br /> 113. 1- 7 s'' 7/,f•Q,r / 4,b B,-a, a B-9V-dna=&tan A,e= toad, <br /> `r Od <br /> 9 s, ° <br /> . -.r,------ ra ,a B,a. b �B=g0--d,a=o sin d,b=o toe d, <br /> Solution of Oblique Triangles <br /> Given Required asi*B . <br /> /a A d - Z 1 d' B'a b' °' C b_ sin d ' C= 180°-(d+B),a sin A <br /> b sia sin C <br /> d, a, b -B,e, C sin B= n d a ,C a 180°-(d fi ,a= sin d <br /> 0.41 s- q <br /> if-1-i `_-/ �.. - t a, b, C A, B,a d+B=180°--C,tan J(d-B)=(°'--b�t b�-•B) <br /> U ,S� .. _a sin C�• 7 c sinal <br /> 1194"" 3 3 7 I o �,B,C e caa+2°,sin fid= $ a -0 <br /> N- ' <br /> a 9 y r 7 7 sin JB= a s ,C_180°-(A+B) <br /> J r ''� _,►-- / (� j. '{ `� a, b, 4 Area 8=a+2.area _ s a a e= C- C) <br /> d, b, c Areab o sin•d <br /> 77 area = 2 <br /> y ar sin B sin C <br /> j 0 A,E,C,a Area area = " <br /> 2 sia'd A. <br /> 3 '3 REDUCTION'.TO HORIZONTAL•, <br /> Rorlso�W Aistance�gl�e distance m�ialisd•by the <br /> e t eevaerotic From <br /> abtanoe i� <br /> s I�cis <br /> Awe _Horlsontal didaspce s>sa �Slove d�raaee mi elope <br /> i' �� / eo Ve dtstanerafaes(tL-costae of t�Rrtksal With tas <br /> aansatlMe as is the the taUmw <br /> Raftantd ei rnuit a': 3:91Eh=.UOi1. <br /> D 7ss�� <br /> 5/ When the rise is R1M d tsa eloped1� <br /> • pnat iess the atlnare IxwLea the slope Vis: rLie=t . <br /> t <br /> • � t <br /> 1b <br /> y <br />